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Rzqust [24]
2 years ago
13

Your little cousin will have a big animal-themed birthday party and you will help with the goody bags. Each bag will have a penc

il, an eraser, and a mini notebook. You searched online and found some cute pencils, erasers, notebooks, and bags to go with the party theme. The pencils come in packages of 10, erasers in packages of 6, mini-notebooks in packages of 15, and bags in packages of 12.
a: How many packages of each should you buy, in order to fill each goody bag and have no leftovers?


b: How many filled goody bags will there be?
Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0

Using the least common factor, it is found that:

  • a) 60 packages should be bought.
  • b) There will be 5 filled goody bags.

<h3>Least Common Factor:</h3>
  • The sizes of the packages are: 10, 6, 15 and 12.
  • To fill each bag and have no left-overs, the number of packages is the <u>least common factor</u> of these amounts.
  • The least common factor is found factoring the numbers into prime factors.

Item a:

10 - 6 - 15 - 12|2

5 - 3 - 15 - 6|2

5 - 3 - 15 - 3|3

5 - 1 - 5 - 1|5

1 - 1 - 1 - 1

Hence, lcf(10,6,15,2) = 2 x 2 x 3 x 5 = 60.

60 packages should be bought.

Item b:

Goody bags are in packages of 12, hence:

60/12 = 5.

There will be 5 filled goody bags.

To learn more about the least common factor, you can take a look at brainly.com/question/24873870

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Answer:

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Let 'M' be the event of selecting males n(M) = 12

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P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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