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Anna11 [10]
3 years ago
8

1) Order the animals by sleep time from least to greatest.

Mathematics
1 answer:
Zolol [24]3 years ago
4 0
The way to line the animals is to put them in order going down. 0.433 56.3% 19/40 65.8%. Then you try to figure out what you need to convert so that you can get your answer. 56.3% changes to 0.563 because you move the decimal two places to the left. 65.8% changes to 0.658 and 19/40 is 0.475. 0.433 0.563 0.475 0.658. Now you compare each row to figure them out. When you do that your answer will be 0.433, 0.475, 0.563, and 0.658. I sleep about 9/24 of the day which is 0.375 and I will fit right befor 0.433.
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A physical fitness association is including the mile run in its high school fitness test. The time for this event is known to po
vlabodo [156]

Answer:

This probability is the p-value of Z given Z = \frac{X - \mu}{\sigma}, considering X as less than X seconds, \mu as the mean and \sigma as the standard deviation.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean \mu, standard deviation \sigma.

Find the probability that a randomly selected high school student can run the mile in less than X seconds.

This probability is the p-value of Z given Z = \frac{X - \mu}{\sigma}, considering X as less than X seconds, \mu as the mean and \sigma as the standard deviation.

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3 years ago
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