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3 years ago

HELP ASAP.....NO LINKS AND NO TROLLING

Mathematics

1 answer:

astra-53 [7]3 years ago

3 0

Answer:

D. $f(x)=x^2$ and $k(x)=x^2-5$

Step-by-step explanation:

The vertex of a function is controlled by the translations of the x and y value. Moving a vertex up and down is connected to the vertical position or the y-value. The y-value is the value that is added to the variable and is not squared.

Vertex form of a function is $f(x)=a(x-h)^2+k$ . In this case, k controls the vertical position of the vertex. If k is negative then the vertex will be moved down. So, if you want to move a vertex down by 5 units, then the k value must be -5.

Plug this into the formula to get the equation for k(x). This means that k(x) must equal $x^2-5$ .

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Slope- Represented by ____ in y = mx + b (what's the blank?)

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Answer:

Step-by-step explanation:

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3 years ago

Find the missing number in the given proportion 3:2=6: ?

Luba_88 [7]

Answer:

6 : 4

Step-by-step explanation:

3 : 2

6 : ?

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3 years ago

The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h

BabaBlast [244]

Answer:

The maximum height of the projectile is 90 ft

Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

in this case is 90 and thus, that is the maximum height of the projectile

8 0

3 years ago

Paul owns a mobile wood-fired pizza oven operation. A couple of his clients complained about his dough at a recent catering, so

Makovka662 [10]

Answer: B. Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the old and the new dough players. The population proportions of customer complaints with the old and new dough would be p1 and p2

P1 - P2 = difference in the proportion of customer complaints with the old and new dough.

The null hypothesis is

H0 : p1 ≥ p2

pm - pw ≥ 0

The alternative hypothesis is

Ha : p1 < p2

p1 - p2 < 0

it is a left tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 6

n1 = 385

P1 = 6/385 = 0.016

For new dough,

x2 = 16

n2 = 340

P2 = 16/340 = 0.047

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (6 + 16)/(385 + 340) = 0.03

1 - pc = 1 - 0.03 = 0.97

z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)

z = (0.016 - 0.047)/√(0.03)(0.97)(1/385 + 1/340) = - 0.031/√0.00553857907

z = - 0.42

Since it is a left tailed test, we would find the p value for the area to the left of the z score. From the normal distribution table,

p value = 0.337

For a 95% confidence level, the significant level, alpha is

1 - 0.95 = 0.05

Since 0.05 < 0.337, we would accept the null hypothesis

Therefore, Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

7 0

3 years ago

A person places $290 in an investment account earning an annual rate of 2.2%, compounded continuously. Using the formula V = Pe^

Tomtit [17]

Answer:

Step-by-step explanation:

Given that the principal p= $290

rate r= 2.2% 2.2/100 =0.022

time t= 18years

by applying the expression

$V = Pe^{rt}$

We have

$V = 290e^{0.022*18}\\\\V=290e^{0.396}\\\\V=290*1.48586931755\\\\V=$430.90$

Hence after 18years the money in the account will be $430.90

8 0

3 years ago