Question

HELP ASAP.....NO LINKS AND NO TROLLING

Answer 1

Answer:

D. $f(x)=x^2$ and $k(x)=x^2-5$

Step-by-step explanation:

The vertex of a function is controlled by the translations of the x and y value. Moving a vertex up and down is connected to the vertical position or the y-value. The y-value is the value that is added to the variable and is not squared.

Vertex form of a function is $f(x)=a(x-h)^2+k$. In this case, k controls the vertical position of the vertex. If k is negative then the vertex will be moved down. So, if you want to move a vertex down by 5 units, then the k value must be -5.

Plug this into the formula to get the equation for k(x). This means that k(x) must equal $x^2-5$.