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valentina_108 [34]
3 years ago
6

Okay Guys plz plz help like really

Mathematics
1 answer:
RSB [31]3 years ago
3 0

Answer:

8

Step-by-step explanation:

Plug in the value of k into your expression and solve.

40-4k^3

40-4(2)^3

40-4(8)

40-32

8

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The coordinates of the intersection of two lines on a graph represent the values of__ and __ when you solve the system of equati
Neko [114]

Answer:

The coordinates of the intersection of two lines on a graph represent the values of <u>x</u> and <u>y</u> when you solve the system of equation.

Step-by-step explanation:


4 0
3 years ago
Heyy can you please help me posted picture of question
vichka [17]
We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\  \\ &#10;x=  \frac{-4+- \sqrt{-12} }{2}   \\  \\ &#10;x= \frac{-4+-2 \sqrt{-3} }{2} \\  \\ &#10;x= -2+- \sqrt{-3}

So, the correct answer to this question is option A
7 0
3 years ago
Need help answering this question tysm! (Picture attached)
snow_lady [41]

Answer:

1 and 2 answers are correct

Step-by-step explanation:

2x-y= -8

x-y = -4

ADD BOTH (y is cancelled)

3x= -12

x= -4

-8+y=-8

y=0

    -4-y = -4

     Multiply all by -1

4+y=4

y=0

       

3 0
3 years ago
A large container holds 5 gallons of water. it begins leaking at a constant rate. After 10 minutes the container has 3 gallons o
dolphi86 [110]
First we have to find how much water leaked
5galllons-3 gallons=2 galllos of water leaked
Now we know\frac{2 galllons}{10 minutes}
Finally we can simplify it\frac{2 gallons}{10 minutes}= \frac{1 gallon}{5 minutes} - its the answer
7 0
3 years ago
Divide <br> (6-q+8q^3-4q^2)/(2q-2)
mestny [16]

Answer:


Step-by-step explanation:

        4q2 + 2q + 3                

 (2q - 2)  l  _  8q3  -  4q2  -  q  +  6                                        

                    8q3  -  8q2                      

                           _  4q2  -  q    

                               4q2 - 4q    

                                     _  3q  +  6  

                                        6q   +  6        

                                       -3q (remainder)  


  4q2 + 2q + 3 -3q / (2q - 2)      


hope this helps

4 0
3 years ago
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