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arsen [322]
3 years ago
8

Pls help. Can’t do this.

Mathematics
1 answer:
Anna [14]3 years ago
6 0

Step-by-step explanation:

The equation of line A:

y-1=0, 5x-3

y=0, 5x-2. Hence its gradient is 0,5

For line B, its you intercept is -8, so y=mx-8.

When x = -4, y=-4m -8 =0 as shown in the graph. This means that m = -2.

Since |-2| > |0, 5|, line B is steeper than line A.

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The first step is to add 7 to both sides, applying the addition property of equality:

-2(4x-1)-7+7=5+7 \iff -2(4x-1)=12

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What's the standard form of 314,207
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8 0
3 years ago
Read 2 more answers
Help please!!
yanalaym [24]

Answer:  (1,-1)

Step-by-step explanation:

Midpoint of BC=(6+4)/2, (3–1)/2. =(5,1)

Slope of BC is (3+1)/4–6)= 4/-2 = -2

Slope of perpendicular bisector of BC =+1/2

Eqn of perpendicular bisector is : Y-1 =1/2 (x-5)

Y=1/2 •(x-5) +1

Midpoint of AB. (6–2)/2, (3–1)/2 ={2,1)

Slope of AB is(3+1)/(-2–6) = 4/-8 =-1/2

Slope of perpendicular bisector = +2

Eqn of perpendicular bisector is Y-1. =2( X-2)

Y=2X-4+1 = 2X -3

Solving Y=(X-5)/2 +1

& Y=2X-3

2X-3 =(x-5/2)+1

2X-4 =(x-5/2)

4X-8 = x-5

3X =3

X=1

Y= 2×1–3= -1

Circumcentre is(1,-1)

8 0
3 years ago
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