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3 years ago

1/4(-12x+16) 10-3(-x-2)

1 answer:

6 0

Alright!
1/4 = 0.25
.25(-12x+16) 7(-x-2)
(-3x + 4)(-7x-14)
21x^2 + 14 x - 56
Do you want me to find the roots or is this enough?
You can do a lot of things with the question you asked, you need to be more specific.

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Which line is the graph of y = x?

satela [25.4K]

B in has the intersection with quadrant 1 and 3

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3 years ago

20 points What is the value of p in the linear equation ? −4 −2 2 4

Nikolay [14]

Answer:

p=-2

Step-by-step explanation:

24p+12-18p=10+2p-6

Subtract what is to the right of the equal sign from both sides of the equation.

24p+12-18p-(10+2p-6)=0

Then pull out the like terms(factors)

Which is: 4p+8

=4(p+2)

Put that to 0 and 4=0 which is not a solution because it's a non-zero constant.

So now put p+2=0, subtract by 2 on both sides and the 2 cancels out and on the right side you have -2

p=-2

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3 years ago

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Pretend like i said sumn funny

vekshin1

Answer:

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3 years ago

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Bethany sells roses and petunias. The expression 3r+2.5p3r+2.5p3, r, plus, 2, point, 5, p gives the cost (in dollars) of rrr ros

Lelechka [254]

Answer: The cost of 7 roses and 8 petunias is $41.

Step-by-step explanation:

Given, Bethany sells roses and petunias. The expression $3r+2.5p$ , gives the cost (in dollars) of r roses and p petunias.

Now to find the cost of 7 roses and 8 petunias , put r= 7 and p= 8 in the above expression , we get

$3(7)+2.5(8)=21+20\\\\=41$

Hence, the cost of 7 roses and 8 petunias is $41.

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3 years ago

Suppose a large shipment of compact discs contained 19% defectives. If a sample of size 343 is selected, what is the probability

Yuri [45]

Answer:

The value is $P( | \^p - p | < 0.04) = 0.9408$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.19$

The sample size is n = 343

Generally given that the ample size is large enough , i.e n > 30 then the mean of this sampling distribution is mathematically represent

$\mu_{x} = p = 0.19$

Generally the standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{p(1- p)}{n} }$

=> $\sigma =\sqrt{\frac{0.19 (1- 0.19 )}{343 } }$

=> $\sigma = 0.0212$

Generally the the probability that the sample proportion will differ from the population proportion by less than 4% is mathematically represented as

$P( | \^p - p | < 0.04) = P( \frac{|\^ p - p |}{ \sigma_p } < \frac{0.04}{0.0212 } )$

$\frac{|\^ p - p |}{\sigma } = |Z| (The \ standardized \ value\ of \ |\^ p - p | )$

$P( | \^p - p | < 0.04) = P( |Z| < 1.887 )$

=> $P( | \^p - p | < 0.04) = P( Z < 1.887 )- P( Z < -1.887 )$

From the z table the area under the normal curve to the left corresponding to 1.887 and - 1.887 is

$P( Z < 1.887 )= 0.97042$

and

$P( Z < -1.887 )= 0.02958$

$P( | \^p - p | < 0.04) = 0.97042 - 0.02958$

=> $P( | \^p - p | < 0.04) = 0.9408$

3 0

2 years ago