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Tatiana [17]
3 years ago
5

The exponent indicates how many times the blank is used as a factor

Mathematics
2 answers:
Fudgin [204]3 years ago
8 0
<span>The answer is base.
The exponent indicates how many times the base is used as the factor.
Base is the number that is multiplied many times as the exponent say so.
For example:
=> 5^7, where 5 is called the base and 7 is the exponent.
Meaning the base number which is 5 needs to be multiplied 7 times.
=> 5 x 5 x 5 x 5 x 5 x 5 x 5
=> the answer is 78 125

</span>



MissTica3 years ago
8 0
For this case suppose that we have an expression of the form:
 a ^ b&#10;
 Where
 a: base of the expression
 b: exponent of the expression
 For example, for a = 2 and b = 3 we have:
 2 ^ 3 = (2) (2) (2)&#10;
 We observe that the base of the expression is used as a common factor of the expression the number of times that the exponent indicates.
 Answer:
 
The exponent indicates how many times the base is used as a factor
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Answer:

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What is 4(2 + a) = 24 <br> a=
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Relationships Between Quantities Quick Check
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Answer: f(1)=2, f(n)= f(n-1) +1 for n>1

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3 years ago
Which value of d is a solution to equation 2.2d + 5.4= 12
ryzh [129]

Hello!

<em><u>Answer:</u></em>

<em><u>d=3</u></em>

<em><u>*The answer must have a positive sign.*</u></em>

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

First, you multiply by 10 from both sides of an equation.

2.2d*10+5.4*10=12*10

Then, you had to refine the problem down.

22d+54=120

Next, you subtract by 54 from both sides of an equation.

22d+54-54=120-54

Simplify.

22d=66

You can also divide by 22 from both sides of an equation.

\frac{22d}{22}=\frac{66}{22}

And finally, simplify and solve. You can also divide by the numbers.

66/22=3

Final answer: → d=3

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D


7 0
4 years ago
Read 2 more answers
Suppose the radius of the sphere is increasing at a constant rate of 0.3 centimeters per second. At the moment when the radius i
elixir [45]
<h2>At the moment when the radius is 24 centimeters, the volume is increasing at a rate of 2171.47 cm³/min.</h2>

Step-by-step explanation:

We have equation for volume of a sphere

             V=\frac{4}{3}\pi r^3

where r is the radius

Differentiating with respect to time,

            \frac{dV}{dt}=\frac{d}{dt}\left (\frac{4}{3}\pi r^3 \right )\\\\\frac{dV}{dt}=\frac{4}{3}\pi \times 3r^2\times \frac{dr}{dt}\\\\\frac{dV}{dt}=4\pi r^2\times \frac{dr}{dt}

Given that

           Radius, r = 24 cm

           \frac{dr}{dt}=0.3cm/s

Substituting

           \frac{dV}{dt}=4\pi r^2\times \frac{dr}{dt}\\\\\frac{dV}{dt}=4\pi \times 24^2\times 0.3\\\\\frac{dV}{dt}=2171.47cm^3/min

At the moment when the radius is 24 centimeters, the volume is increasing at a rate of 2171.47 cm³/min.

4 0
3 years ago
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