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3 years ago

Determine a when d=6, g=4, k=3

Mathematics

1 answer:

tigry1 [53]3 years ago

8 0

I think your missing another part to your question because this doesn't really make sence...

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A parabola and a circle are graphed into the standard (x,y) coordinate plane. The circle has a radius of 4 and is centered at (1

Gala2k [10]

Answer:

Correct answer: Two point of intersection and one touch point.

Step-by-step explanation:

Cartesian form of parabola is: y= a(x-1)² + 5 and point named A(2,4)

when we replace the coordinates of the point A in the formula we get

a = - 1 and parabola is y= - (x-1)² + 5 which means that it faces the opening downwards. The parabola touches the circle in vertex.

God is with you!!!

6 0

3 years ago

Convert 3.2 meters to centimeters

Neporo4naja [7]

Answer:

320

Step-by-step explanation:

multiply by 10 and get rid of the decimal

3 0

3 years ago

Read 2 more answers

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

2 years ago

Can someone help please

Pepsi [2]

Answer:

A: 5

B: 6

C: 3x^2 - 2x

D: 8

E: 22

Step-by-step explanation:

A: (-1)^2 + 4 = 5

B: (-4)^2 +4 = 16

2 x (-3) -4 = -10,

16-10=6

C: 3(x^2 + 4) = 3x^2 + 12

3x^2 + 12 -2x -4, simplify

3x^2 - 2x

D: g(3) = 2*3 -4 = 2

f(2) = 2^2 +4 = 8

E: f(3) = 3^2 + 4 = 13

g(13) = 2*13 - 4 = 22

6 0

3 years ago

Please hwelp please

Fantom [35]

Answer:

2⁸ > 2.38 × 10² > 6³ > 2.16 × 10¹ > $\sqrt{300}$ , 300%

Step-by-step explanation:

Given numbers are,

2.38 × 10², √300, 2⁸, 300%, 6³, 2.16 × 10¹

We have to arrange these numbers in the decreasing order(from greatest to least)

2.38 × 10² = 2.38 × 100 = 238

√300 = 10√3 ≈ 17.32

2⁸ = 256

300% = $\frac{300}{100}$ = 3

6³ = 216

2.16 × 10¹ = 21.6

Therefore, decreasing order (from the greatest to least) will be,

256 > 238 > 216 > 21.6 > 17.32 > 3

2⁸ > 2.38 × 10² > 6³ > 2.16 × 10¹ > $\sqrt{300}$ , 300%

5 0

3 years ago