Answer:
x=3
Step-by-step explanation:
2x+3=9
2x=6
x=3
Answer:
The above triangle is an isosceles triangle....
Reason
As we can see AB and DE are parallel to each other
As angle ABC is 80 degree
Therefore BCE is too 80 degree (as they both are alternate to each others)
Hence angle DCB is a 50 degree because in the straight DCE we have angle BCE as <u>80 </u><u>degree</u><u> </u>and Angle ACD as <u>50 degree</u>
Since a straight line has <u>180 degree</u> therefore the remaining angle ACB is 50 degree(180-80-50)
Now in triangle BAC. Angle C is 50 degree and Angle B is 80 degree, since the total angle of a triangle is 180 degree therefore A is 50 degree that is angle BAC is 50 degree(180-50-80) .
Hence here we see that two opposite sides have same angle that is the reason its a ISOSCELES triangle
Answer BY AN INDIAN
THANK YOU
Estimate- 4,520
if you multiply -371954
Adding- 1779
Let <em>w</em> be the wind speed and <em>p</em> the plane's speed in still air.
Flying against the wind, the plane has velocity
<em>p</em> - <em>w</em> = 390 mi/h
and flying with it, it has
<em>p</em> + <em>w</em> = 470 mi/h
Add the two equations together to eliminate <em>w</em> and solve for <em>p</em> :
(<em>p</em> - <em>w</em>) + (<em>p</em> + <em>w</em>) = 390 mi/h + 470 mi/h
2<em>p</em> = 860 mi/h
<em>p</em> = 430 mi/h
Subtract them to eliminate <em>p</em> and solve for <em>w</em> :
(<em>p</em> - <em>w</em>) - (<em>p</em> + <em>w</em>) = 390 mi/h - 470 mi/h
-2<em>w</em> = -80 mi/h
<em>w</em> = 40 mi/h
