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3 years ago

Solve for:

Mathematics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer:

5.59

Step-by-step explanation:

875 = 5x^3

175 = x^3

So x =5.59

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The value of which of these expressions is closest to e?

mars1129 [50]

Answer:

Step-by-step explanation:

Given: expressions

To find: the expression whose value is closest to e

Solution:

Value of e is 2.718

$\left ( 1+\frac{1}{19} \right )^{19}=\left ( \frac{20}{19} \right )^{19}=2.65\\\left ( 1+\frac{1}{22} \right )^{22}=\left ( \frac{23}{22} \right )^{22}=2.659\\\left ( 1+\frac{1}{20} \right )^{20}=\left ( \frac{21}{20} \right )^{20}=2.653\\\left ( 1+\frac{1}{21} \right )^{21}=\left ( \frac{22}{21} \right )^{21}=2.656$

Therefore, value 2.659 is closest to the value of e.

So, option B. is correct.

7 0

3 years ago

Katie's swim team is having an end-of-season pizza party. When the party started, there were 50 slices of pizza. Now there are 2

ss7ja [257]

Answer:

i think its c im not sure so it might be wrong im so sorry if its wrong

Step-by-step explanation:

6 0

3 years ago

Simplify the expression.<br><br> 55−4⋅5+12

Lunna [17]

Your answer is 62.5. Hope i helped

4 0

3 years ago

Read 2 more answers

Tomas ia savin $17.00 each week to buy new sewing machine that costs 175.50.How many weeks will he have to save to have enough m

MatroZZZ [7]

X=number of weeks
We can suggest this inequation:
17x>175.5
x>175.5/17>10.323>11 (the solution have to be a whole number, therefore the answer will be 11 weeks or more)

Answer: Tomas need save money during 11 weeks.

4 0

3 years ago

Plz help me!!!!!!!!!

Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

7 0

3 years ago