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2 years ago

Simplify to create an equivalent expression. −5(1−5k)−4(2k+5)

Mathematics

2 answers:

BabaBlast [244]2 years ago

7 0

Answer:

17 k + -25

Step-by-step explanation:

Simplify the following:

-5 (1 - 5 k) - 4 (2 k + 5)

-5 (1 - 5 k) = 25 k - 5:

25 k - 5 - 4 (2 k + 5)

-4 (2 k + 5) = -8 k - 20:

25 k + -8 k - 20 - 5

Grouping like terms, 25 k - 8 k - 20 - 5 = (25 k - 8 k) + (-5 - 20):

(25 k - 8 k) + (-5 - 20)

25 k - 8 k = 17 k:

17 k + (-5 - 20)

-5 - 20 = -25:

Answer: 17 k + -25

Mandarinka [93]2 years ago

3 0

The answer is 17k-25

Hope that helps!

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Find the slope of the line passing through the points (-5,5) and (-5,-8)

AysviL [449]

Answer:

Step-by-step explanation:

5-8 -3

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-5--8 -3

-3

-----= 1

-3

Hope this helps!

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3 years ago

Read 2 more answers

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ivanzaharov [21]

Answer:

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Step-by-step explanation:

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2 years ago

Chloe wants to cut a 37 in. piece of ribbon into three pieces. The second piece is to be 2 in. longer than the first, and the th

valentinak56 [21]

1st piece = x

2nd piece = x+2

3rd piece = x+2+3 = x+5

37 = x +x+2 + x+5 =

37 = 3x+7

30=3x

x = 30/3 = 10

1st piece = 10 inches

2nd piece = 10+2 = 12 inches

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3 years ago

Please help me with the question

Damm [24]

Answer:

The right answer is Option 2:

$y+6 = -\frac{3}{4}(x-2)$

Step-by-step explanation:

Point-slope form of equation of a line is given by:

$y-y_1 = m(x-x_1)$

Here m is slope of the line and (x1,y1) is the point from which the line passes.

Given

Slope = m = -3/4

Point = (x1,y1) = (2,-6)

We simply have to put these value into the general form of equation of line in point-slope form

$y-(-6) = -\frac{3}{4}(x-2)\\y+6 = -\frac{3}{4}(x-2)$

Hence,

The right answer is Option 2:

$y+6 = -\frac{3}{4}(x-2)$

7 0

2 years ago

A company estimates that it will sell ????(x) units of a product after spending x thousand dollars on advertising, as given by ?

zepelin [54]

Answer:

$(11\frac{1}{3},20)$

Step-by-step explanation:

If the Number of Sales of x units, N(x) is defined by the function:

$N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40$

$N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}$

Next, we text the critical points and the end points of the interval to see where the derivative is increasing.

$N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600$

Thus, the rate of change of sales $N'(x)$ is increasing in the interval $(11\frac{1}{3},20)$ on 10≤x≤40.

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2 years ago