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3 years ago

1. Compare the fraction.

1 answer:

4 0

1. 1/6 < 5/6 - answer A.
2. 4/7 (?) 1/6
First fraction is bigger, to check it, make both fractions to be x/42, so 24/42 > 7/42 - answer A.

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A display of cans in a grocery store consists of 15 rows. There are 45 cans on the bottom , 42 cans on the next row, and so on,

Alchen [17]

Answer:

n = 9

Step-by-step explanation:

20 + 18 + ... + 6 + 4

---------------------------

a = 20 ; d = -2 ; n = ?

--------

4 = 20 + (n-1)(-2)

-16 = (n-1)(-2)

---------

n-1 = 8

n = 9

-------

S(9) = (9/2)(20+4)

S(9) = 4.5*24

S(9) = 108

8 0

3 years ago

angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as

Gwar [14]

We know that
sin²x+cos²x=1
so
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

the answer is
cos o=√21/5

7 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago

Can someone help me with B? I’m really bad at this kind of stuff. I need help ASAP

Vinil7 [7]

Answer:

D = .44P

Step-by-step explanation:

We need to find the slope of the line

m = (y2-y1)/ (x2-x1)

Using two points

m = (22-4.4) /(50-10)

= 17.6/40

= .44 lb/ in^2 ft

We can use the point slope form of the equation

y-y1 = m(x-x1) where y=D and x=P

D-4.4 = .44 (P-10)

Distribute

D-4.4 = .44P - 4.4

Add 4.4 to each side

D -4.4+4.4 = .44P -4.4+4.4

D = .44P

8 0

3 years ago

Read 2 more answers

The director of a state agency believes that the average starting salary for clerical employees in the state is less than $35 c

MrRissso [65]

Answer:

There is not enough evidence to conclude that average starting salary for clerical employees in the state is less than $35,000 per year.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 35,000 dollars per year

Sample mean, $\bar{x}$ = 34,700 dollars per year

Sample size, n = 100

Alpha, α = 0.10

Population standard deviation, σ = 3,500 dollars per year

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 35,000\text{ dollars per year}\\H_A: \mu < 35,000\text{ dollars per year}$

We use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{34700 - 35000}{\frac{3500}{\sqrt{100}} } = -0.8571$

Now, $z_{critical} \text{ at 0.10 level of significance } = -1.28$

Since,

$z_{stat} > z_{critical}$

We fail to reject the null hypothesis and accept the null hypothesis.

Thus, there is not enough evidence to conclude that average starting salary for clerical employees in the state is less than $35,000 per year.

3 0

3 years ago