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3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

crimeas [40]3 years ago

3 0

Denali- 6.7x70= 469

The building should be strong enough to withstand an earthquake of that magnitude.

Rat Island- 7.8x30=234

The building should be string enough to withstand an earthquake of that magnitude.

Hope this helps! ;)

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A line passes through the point (2, 3) and has an undefined slope, what is the equation of the line? A) y = 2 B) y = 3 C) x = 2

Harman [31]

"Undefined" slope means the line is vertical, of the form x = constant. The constant is the x-value of the point the line goes through.

C) x = 2

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3 years ago

3) 4 pounds of meat cost $18. How much will 10 pounds of the same meat cost?

Ganezh [65]

Answer:

$45

Step-by-step explanation:

4 lbs = $18

2 lbs = $9

10 lbs = $45

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3 years ago

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The sum of two trinomials is 6x2 − 5x + 4. If one of the trinomials is 4x2 + 3x − 2, then what is the other trinomial?

Vadim26 [7]

Subtract the known trinomial from the total sum:

6x2 - 5x + 4 - 4x2 + 3x - 2 = 2X^2 -8x +6
I hope this helps :)

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2 years ago

QUESTION : A family of four went out to dinner. Their bill came to $156.98 and they want to leave a 15% tip. How much the tip wi

Rama09 [41]

Answer:

tip = $23.55

Step-by-step explanation:

156.98 x 0.15 = 23.55

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3 years ago

Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

3 years ago