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2 years ago

7

Please help me with this homework

1 answer:

nignag [31]2 years ago

8 0

$2.40 add all the values of the coins together

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A playground is being designed where children can interact with their friends in certain combinations.

levacccp [35]

Answer:

17

Step-by-step explanation:

I think 17

4 0

2 years ago

Ishaan is 72 years old and William is 4 years old. How many years will it take until Ishaan is only 5 times as old as William?

KiRa [710]

72+x=5(4+x) solve for x.

4 0

3 years ago

Name the legs of abc

Diano4ka-milaya [45]

It looks as if "B" is the right angle so
AC is the hypotenuse
AB and BC are the legs

3 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago

a rectangular pyramid has a volume of 190 cubic centimeters. Find two possible sets of measurements for the base area and height

DerKrebs [107]

<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>

<em><u>Solution:</u></em>

<em><u>The volume of rectangular pyramid is given as:</u></em>

$Volume = \frac{1}{3} \times base\ area \times height$

Given that,

<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>

<em><u></u></em> $190= \frac{1}{3} \times base\ area \times height$ <em><u></u></em>

<em><u>Substitute, base area = 570 and height = 1</u></em>

Then we get,

$190 = \frac{1}{3} \times 570 \times 1\\\\190 = 190$

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively

<em><u>Substitute, base area = 285 and height = 2</u></em>

$190 = \frac{1}{3} \times 285 \times 2\\\\190 = \frac{1}{3} \times 570\\\\190 = 190$

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively

6 0

3 years ago