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kipiarov [429]
3 years ago
11

Jerome works as a waiter. He earns $80 each weekend plus 15% in tips based on the cost of the meals served.

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

He gets paid $80 each weekend, and a 15% with tips.

you would need to figure out the tips, by taking the $725 and timesing it by .15 for the percent.

which would be 108.75

you would now take 108.75 and add 80 to get what he made that weekend.

108.75+80 = 188.75 dollars

Step-by-step explanation:

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Tyler has 3 times as many books as Mai.
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Answer:

a. x divided by 3

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An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there
goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

(a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?

(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

P(F) = 0.17

P(O) = 0.40

A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

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3 years ago
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Taking over his thoughts is the answer
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2 years ago
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Jlenok [28]
<h3>Answer:</h3>

\displaystyle x^{\frac{2}{3}}

<h3>Step-by-step explanation:</h3>

The rules of exponents tell you ...

... (a^b)(a^c) = a^(b+c) . . . . . . applies inside parentheses

... (a^b)^c = a^(b·c) . . . . . . . . applies to the overall expression

The Order of Operations tells you to evaluate inside parentheses first. Doing that, you have ...

... x^(4/3)·x^(2/3) = x^((4+2)/3) = x^2

Now, you have ...

... (x^2)^(1/3)

and the rule of exponents tells you to multiply the exponents.

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3 years ago
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