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Rzqust [24]
3 years ago
10

All 12 12 members of the glee club went to eat at the Hibachi Grill restaurant. The chicken costs $10 $10 per person, while the

beef costs $14 $14 per person. At the end of the evening, the club members received a bill for $136 $136 , not including tax.
Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0

Answer:

8 chicken and 4 beeff

Step-by-step explanation:

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If elephant grows 3 3/4 inched a day, how many inches will it grow in 7 days?
olga nikolaevna [1]

Answer:

26.25, or 26 1/4, inches

Step-by-step explanation:

each day 3.75inches, so in 7 day, it grows 3.75 * 7 = 26.25inches

4 0
1 year ago
What is a triangle with at least two congruent sides and two congruent angles​
pochemuha

Answer:

isosceles triangle

Step-by-step explanation: an isosceles triangle has 2 congruent sides, and 2 congruent angles

7 0
3 years ago
The figure is made by attaching semicircles to each side of an 11-ft-by-11-ft
vova2212 [387]

Answer:

by how much degrees should the heat be reduced in the last 5 minutes of banking

6 0
3 years ago
When Kirk and Elisa formed their general partnership, Kirk contributed 90 percent of the capital, and Elisa contributed 10 perce
topjm [15]

Answer:

Her share is $3500

Step-by-step explanation:

As a general rule, if they did not make any specifications on how they would share the profit, then they should share it according on how percentage of capital they contributed. Since Elisa only contributed 10%, then she should get only 10% of profit, as a result, her share is 35000*0.1 = $3500.

3 0
3 years ago
A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c
slava [35]

Answer:

I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

\frac{dI}{dt}=a*I*(1000-I)

Rearranging and integrating

\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t

At the initial breakout (t=0) there was one trooper infected (I=1)

-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755

In two days (t=2) there were 5 troopers infected

-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725

Rearranging, we can model the number of infected troops (I) as

-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755}  \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

6 0
2 years ago
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