(7x -7) + (6x +6) = 90
take away the parenthesis: 7x - 7 + 6x + 6 = 90
combine like terms: 13x - 1 = 90
add 1 to both sides: 13x = 91
divide both sides by 13: <span>x = 7.
Now: substitute x = 7 into the angles: the first angle is 42 degrees, the second angle is 48 degrees</span>
Distributive property is in the form of:<span>
a (b+c) = ab + bc</span>
<span>
In this case, we try writing 47 as:</span>
47 = 50-3 or 47 = 40+7
Therefore:<span>
11 x 47 = 11 x (50-3) = 11 x 50 - 11 x 3 = 550 - 33 =
517
or
<span>11 x 47 = 11 x (40+7) = 11 x 40 + 11 x 7 = 440 + 77 =
517</span></span>
Answer:
Step-by-step explanation:
I have the same question :(((
sry
Answer:
Step-by-step explanation:
4y - 16 + 68 = 180
4y + 52 = 180
4y = 128
y = 32
2x - 24 = 68
2x = 92
x = 46
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
