The area of rectangle with length l and width w is

If the length of rectangle is expressed as
and the width of rectangle is expressed as
, then the area of rectangle is

Answer:
86
Step-by-step explanation:
<u>Perimeter of WXY = WSY+WRX+XY</u>
<em>--> WSY = SY x 2</em>
--> WSY = 16 x 2 = 32
<em>Since it is an isosceles triangle, WRX = WSY</em>
--> WRX = 32
<em>--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.</em>
<em>--> Solve it using the cos theta rule</em>
--> Angle = Angle X = 70°
Hypotenuse = WRX = 32
Adjacent = WA = ?
<em>--> Cos (Angle) = Adjacent/Hypotenuse</em>
Cos (70) = WA/32
WA = 10.9 rounded off to 11
--> WA=AY= 11
--> XY = WA + AY = 11+11 = 22
<em>--> Perimeter = WSY+WRX+XY</em>
Perimeter = 32+32+22
Perimeter = 86
Therefore, the perimeter of WXY is 86.
Missing part of the question:
Write an inequality to determine the number of articles, M could have written for the school newspaper.
Answer:
The inequality: 
The solution: 
Step-by-step explanation:
Given
From the question, we have the following parameters:



Required
Determine the inequality to solve for M
Substitute the values for H and G in the inequality:


Multiply through by 4



Divide both sides by 11

Answer:
Angle 2 is 36 degrees
Step-by-step explanation:
73 - 37 = 36