Write the equation of a line that is parallel to the y axis and passes through the point (-2,5).

Mathematics

1 answer:

dybincka [34]2 years ago

3 0

Answer:

x = -2

Step-by-step explanation:

If it’s parallel to the y-axis, it must be an x value that is straight up and down. The x coordinate here is -2 so the line must be vertical from -2 on the x-axis.

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Find the following integral. <br> Integrate x + 5/x^2 +10x +26 dx

sweet-ann [11.9K]

Given :

Polynomial , $f(x)=x+\dfrac{5}{x^2}+10x+26$ .

To Find :

Integration of f(x) .

Solution :

We know , integration of $x^n$ is :

$\int x^n \, dx = \dfrac{x^{n+1}}{n+1}+C$

( Here , is C is a constant )

Now ,

$\int f(x)\ dx=\int( x+\dfrac{5}{x^2}+10x+26)dx\\ \\ \int f(x)\ dx= \int x\ dx+\int 5x^{-2}\ dx+\int 10 x \ dx +26\ dx\\ \\ \int f(x)\ dx=\dfrac{x^2}{2}+\dfrac{5\times x^{-1}}{(-1)}+\dfrac{10x^2}{2}+26x+C\\\\ \int f(x)\ dx=\dfrac{11x^2}{2}+26x-5x^{-1}+C$