Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18






<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
 
        
                    
             
        
        
        
F - g(2) = 3x^2 + 1 - ( 1 - x )
 = 3x^2 + 1 - 1 + x
 = 3x^2 + x
 = 3(2)^2 + 2
 = 14
the answer is B.14
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Answer:
24.08
Step-by-step explanation:
We use the Pythagorean theorem and we get (16)^2 + (18)^2 = (x)^2
256 + 324 = x^2
x^2 = 580
x is about 24.08.