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WARRIOR [948]
3 years ago
12

You want to know the side length of the square swimming pool. Explain how you can use the perimeter then find the side length to

the nearest yard. The perimeter of the pool is 100 yards. Please solve due in 20 minutes
Mathematics
1 answer:
olganol [36]3 years ago
4 0

Its a square pool and its perimeter is 100 yards.

We know that a square has 4 sides with the same length so we can give a square perimeter by the sum of their 4 sides

Lets call the side "l" and since we have 4 of them we need to sum it 4 times

l + l + l + l = perimeter

4l = perimeter

We know the perimeter

4l = 100

Divide both sides by 4

4l/4 = 100/4

l = 25

So the side length is equal to 25 yards

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Factor tree for 30 and 54
elena-14-01-66 [18.8K]

Answer:

30|2

15|3

5|5

1

54|2

27|3

9|3

3|3

1

5 0
4 years ago
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The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

6 0
3 years ago
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If f(x) = 3x^2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?
ziro4ka [17]
F - g(2) = 3x^2 + 1 - ( 1 - x )
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= 3x^2 + x
= 3(2)^2 + 2
= 14

the answer is B.14

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4 0
3 years ago
Help me on this please !
inna [77]

Answer:

24.08

Step-by-step explanation:

We use the Pythagorean theorem and we get (16)^2 + (18)^2 = (x)^2

256 + 324 = x^2

x^2 = 580

x is about 24.08.

7 0
2 years ago
SOMEONE HELP ME PLEASE WITH THESE PROBLEMS AND PLEASE SHOW YOUR WORK FOR 50 points and BRAINLIEST THANK YOU
ELEN [110]

<u>Answer</u>:

13. 6x^7 y^7   ||     14. \frac{25x^4}{y^6}

<u>explanation</u>:

13.

\frac{12x^9 y^5}{2x^2 y^-2}

6x^{9-2} y^{5--2}

6x^7 y^7

14.

(\frac{5y^{-3} }{x^{-2} } )^{2}

(\frac{5y^{-3} }{x^{-2} } )(\frac{5y^{-3} }{x^{-2} } )

\frac{\frac{25}{y^6}}{\left(x^{-2}\right)^2}

\frac{\frac{25}{y^{-6} }}{\left(x^{-4}\right)}

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2 years ago
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