Answer:
We are observing the galactic center as it was 27,000 years ago
Step-by-step explanation:
The Galactic Center, or Galactic Centre, is the rotational center of the Milky Way. It is 8,122 ± 31 parsecs (26,490 ± 100 ly) away from Earth in the direction of the constellations Sagittarius, Ophiuchus, and Scorpius where the Milky Way appears brightest. It coincides with the compact radio source Sagittarius A*
Common denominator would be 40, 3/4 becomes 30/40, 1/5 becomes 8/40, 5/8 becomes 25/40. 10 30/40 + 6 8/40 + 12 25/40 = 28 63/40 = 29 23/40
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Answer:
Length of side a = 4.30 miles
Incomplete question:
The area of the regular polygon is 48 mi2. What is the length of side a? miles
Step-by-step explanation:
The number of sides of sides of the polygon is not given, so we will assume the polygon is an hexagon as shown in the attached image;
Given;
Area = 48 mi^2
Area of an hexagon using side a can be written as;
A = (3/2)√3×a^2
Making a the subject of formula
a = √(2/3√3 ×A)
Substituting the values
a = √(2/3√3 ×48)
a = √(32/√3)
a = 4.30 miles
ii and iii
polynomials are functions of quadratic,cubic,quartic etc involving only a non negative integer power of x.
since option (i) includes negative power(5x^-2) and option iv is a rational function
but option iii can be simplified to a polynomial function (x^2+(4x^3/2-1/2))=x^2+4x^2/2=x^2+4x