Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?
2 answers:
Answer:
-10 is the correct answer to the given question .
Step-by-step explanation:
Missing information:
Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below
Triangle PQR has vertices It is translated according to the rule
. What is the y-value of P'?
Now coming to the solution as already mention in the question
The translated rule is
Now calculated the vertices P value according to the rule of translated
So -10 is the value of y in P vertices .
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Answer:
The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 .
Step-by-step explanation:
Given as :
The line equation is y = x
Now, equation of line in slope-intercept form y = m x + c
where m is the slope of line and c is y-intercept
Comparing given line equation with standard line equation
The slope of line y = x is m = 1
Again
Other line is passing through point (2 ,2) and is perpendicular to line y = x
Let The slope of other line = M
∵ From perpendicular lines property
Product of slope of lines = - 1
i.e m × M = - 1
Or , M =
Or, M =
∴ M = - 1
<u>Now, Equation of other line in point-slope form</u>
The other line is passing through point (2 , 2) and slope M = - 1
So, y - = M × (x -
)
Or, y - 2 = - 1 × ( x - 2 )
Or, y - 2 = - x + 2
Or, y = - x + 2 + 2
Or, y = - x + 4
Hence, The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 . Answer