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Aleksandr [31]
3 years ago
14

Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?

Mathematics
2 answers:
slega [8]3 years ago
9 0

Answer:

d. -10

Step-by-step explanation:

steposvetlana [31]3 years ago
6 0

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices P(-2, 6), \ Q(-8, 4), and\  R(1, -2). It is translated according to the rule    (x, y)\ -> \  (x\  - \ 2, y\  - 16). What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is (x, y)\  -> (x - 2, \ y -16).

Now calculated the vertices P value according to the rule of translated

P(-2, 6)\\Now \  apply \ the\ translated\ rule \ in\  P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)

So -10 is the value of y in P vertices .

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