Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?

Mathematics

2 answers:

slega [8]3 years ago

9 0

Answer:

d. -10

Step-by-step explanation:

steposvetlana [31]3 years ago

6 0

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices $P(-2, 6), \ Q(-8, 4), and\ R(1, -2).$ It is translated according to the rule $(x, y)\ -> \ (x\ - \ 2, y\ - 16)$ . What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is $(x, y)\ -> (x - 2, \ y -16).$

Now calculated the vertices P value according to the rule of translated

$P(-2, 6)\\Now \ apply \ the\ translated\ rule \ in\ P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)$

So -10 is the value of y in P vertices .

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