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alukav5142 [94]
3 years ago
8

Suppose you cut a small square from a square of fabric as shown in the diagram. Write an expression for the remaining shaded are

a. Factor the expression. Type your answer below.

Mathematics
2 answers:
eduard3 years ago
4 0
The area of the larger square is x^2
The area of the small square is 3*3 = 9
To find the area of the shaded region you subtract the two values.
x^2 - 9

The factored form of this is (x + 3)(x - 3)
Nikitich [7]3 years ago
3 0

Answer:

(x+3)(x-3)

Step-by-step explanation:

we know that

The remaining shaded area is equal to the area of the complete square minus the area of the small square

so

The area of complete square is equal to

A1=x^{2}\ units^{2}

The area of the small square is equal to

A2=3^{2}=9\ units^{2}

The area of the remaining shaded area is equal to

A1-A2=(x^{2} -9)\ units^{2}

(x^{2} -9)\ units^{2}=(x+3)(x-3))\ units^{2}

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The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1
evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193

The 98% confidence interval for the population mean is (2146, 2193).

3 0
3 years ago
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