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PilotLPTM [1.2K]
3 years ago
6

(ab^2 x -b^4a^3)^2 What is the answers

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

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When a product fails to perform as warranted, this is called a) contractual liability. O b) product malfunction. c) malicious manufacture. d) breach of warranty
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3 years ago
The measurement of the three interior angles of a quadrilaterals are: 85 °, 54 ° and 96 °, what is the measurement of the fourth
Diano4ka-milaya [45]
<h2><u>Question</u>:-</h2>

The measurement of the three interior angles of a quadrilaterals are: 85 °, 54 ° and 96 °, what is the measurement of the fourth angle?

<h2><u>Answer</u>:-</h2>

<h3>Given:-</h3>

The measurement of the three interior angles of a quadrilaterals are: 85 °, 54 ° and 96 °

<h3>To Find:-</h3>

The measurement of the fourth angle.

<h2>Solution:-</h2>

By angle sum property of a quadrilateral,

Sum of all the interior angles = 360 °

So, let the fourth angle be x

\therefore 85 ° + 54 ° + 96 ° + x = 360 °

\therefore 235 ° + x = 360 °

\therefore x = 360 ° - 235 ° = 125 °

<h3>The measurement of the fourth angle is <u>1</u><u>2</u><u>5</u><u> </u><u>°</u>. [Answer]</h3>
3 0
3 years ago
if trapezium of area 140 cm horsepower sides 10 cm apart and one of them decides is 16 cm longfind the area find the length of t
Vilka [71]

Given :

  • Area of the trapezium is 140 cm².
  • Its height is 10 cm.
  • One of the parallel side is 16 cm.

To Find :

  • The other parallel side.

Solution :

  • Let the other parallel side be x

We know that,

{ \qquad \: \pmb{ \dfrac{1}{2} \times (sum \: of \: the \: parallel \: sides) \times height} = \pmb{Area_{(trapezium)}}}

Now, Substituting the given values in the formula :

\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times (16 + x)\: \times 10 \: = {140}}}}

\qquad { \dashrightarrow \: { \sf{ 5 \times (16 + x)\  \: = {140}}}}

\qquad { \dashrightarrow \: { \sf{ 80 + 5x = {140}}}}

\qquad { \dashrightarrow \: { \sf{  5x = {140 - 80}}}}

\qquad { \dashrightarrow \: { \sf{  5x = {60}}}}

\qquad { \dashrightarrow \: { \sf{  x = { \dfrac{60}{5} }}}}

\qquad { \dashrightarrow \: { \pmb{  x = { 12 }}}}

Therefore,

  • The other parallel side of the trapezium is 12 cm.
8 0
2 years ago
Can somebody please help
quester [9]

Answer:

Every equation has a solution.

Hope that helps!?

Step-by-step explanation:

8 0
3 years ago
A rectangular picture frame has a length that is 6 cm greater than the width. The total perimeter is 36
Elan Coil [88]

Answer:

Step-by-step explanation:

width= x

length= x+6

perimter  = 2x+ 2(x+6)

36= 2x+ 2x+ 12

36= 4x + 12

36-12= 4x

4x= 24

x= 6

therefore width= 6cm

length= 6+6 = 12

3 0
2 years ago
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