I am positive the answer I C.
Answer:
Hi there, you can use Pitagoras relationship to solve this up (Without using any other "tool".
Point A is located wheter in (-6,8) or could be located in (-6,8)
Step-by-step explanation:
Point A is 10 units away from the origin, and its x coordinate is -6, using this information, you can draw a triangle from 0 to -6 (the basis) and using 10 as the hypotenuse, so, you have this equation:
![H^{2} = x^{2} +y^{2}](https://tex.z-dn.net/?f=H%5E%7B2%7D%20%3D%20x%5E%7B2%7D%20%2By%5E%7B2%7D)
solving for Y variable, you have this
y=±![\sqrt{10^{2}-(-6)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B10%5E%7B2%7D-%28-6%29%5E%7B2%7D%20%20%7D)
Note the combined sing ±, meaning that y=8 is a valid answer and that y= -8 is also a valid answer.
Hope It helps
The answer is 6 (x + 5) (x - 5)
It should be 64 hope it helps