IM TAKING AN EXAM HELPPPP!!!!

Your water bill consists of five parts: A base hookup fee of $32.50, a water fee of $0.03 per gallon of water, a sewer fee of $0

Taya2010 [7]

hi

You have to keep calm and to treat data as it come.

1 ) Start by constant fees :

hook up fees is 32.50 and trash collection fees are 35

so contant fees : 32.50 +35 = 67.50

2 ) Now we have to deal with variable fees which depend on how much water is used

water fees :

0.03 per gallon, and we have 4 000 gallon, so :

0.03*4 000 = 120

Sewer fees :

0.01 per gallon, and we have 4 000 gallon, so :

0.01 * 4000 = 40

3 ) Total before taxation we have :

67.50 +120 +40 = 227.5

4) Now we apply tax on the total before tax.

tax is 5 % , which mean you rise the "off tax " price by 5 percent.

To grow a number of X % , you multiply by 1+ X/ 100

here X = 5 so the multiplicator is : 1 + 5/100 = 1.05

So total of the bill is : 227.5 * 1.05 = 238.875

The water compagny is probably going to round it up to 238.88

4 0

1 year ago

determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50

Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

$\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}$

x is 3/2. Replace this value in both expression to find the measure of each angle.

$\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}$

The measure of these angles is 47°

7 0

2 years ago

Carlos wants to practice piano 2 hours each day. He practices piano for 3/4 hour before school and 7/10 hour when he gets home.

CaHeK987 [17]

Answer:

Carlos has practiced piano for $\frac{29}{20}=1\frac{9}{20}$ hours.

Carlos needs to practice $\frac{11}{20}$ hours.

Step-by-step explanation:

We have been given that Carlos wants to practice piano 2 hours each day. He practices piano for 3/4 hour before school and 7/10 hour when he gets home.

First of all, we will find piano practiced before school and after school by adding both amounts as:

$\frac{3}{4}+\frac{7}{10}$