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marishachu [46]
3 years ago
9

The length of an object's shadow varies directly with It's heigt. If a can is 13 cm tall casts a shadow that is 7.5 cm long, a b

ottle that is 2.5 cm tall will cast a shadow that is approximately 14.2 cm long.
Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0
X = Can/Bottle height, y = Shadow length
x = 13 cm, y = 7.5 cm
x = 2.5 cm, y = 14.2 cm
I'm assuming your question is asking for an equation to model this. Since there are only two data points the only equation that can be made is linear
y = mx + c
m = (y2 - y1)/(x2 - x1) <- Let 14.2 be y2, and 2.5 be x2 (it is important)
m = (14.2 - 7.5)/(2.5 - 13)
m = 6.7/-10.5
m = -0.638
y = -0.638x + c
To find c we can sub any one of the two coordinates, 
i'm choosing (2.5,14.2)
14.2 = -0.638(2.5) + c
14.2 = -1.595 + c
14.2 + 1.595 = c
15.795 = c
So the final equation is y = -0.638x + 15.795
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Jeff has a density of 1000 g/mL and a volume of 25-mL. What is Jeff’s mass?
zlopas [31]

Answer:

25,000 grams

Step-by-step explanation:

Density can be found using the following formula:

d=\frac{m}{v}

If we rearrange the formula for m, mass, we will multiply both sides of the equation by v.

d*v=\frac{m}{v}*v

d*v=m

The mass can be found by multiplying the density by the volume.

Jeff's density is 1000 grams per milliliter and his volume is 25 milliliters.

d= 1000 g/mL\\v=25 mL

Substitute the values into the formula.

m=d*v

m= 1000 g/mL * 25 mL

Multiply. When you multiply, the "mL" or milliliters will cancel out.

m= 1000 g * 25

m= 25000 g

Jeff's mass is 25,000 grams.

6 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
How to do it ? plz answer it..​
Vera_Pavlovna [14]

I hope you understand....

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Sholpan [36]

Answer:

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60 is 1/100 of what? ​
Thepotemich [5.8K]

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