C=2161
.........................
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
Answer:
7 Hours 12 Minutes
Step-by-step explanation:
So they one of the printer increases at a rate of 1/12 and the other increases at a rate of 1/18. Since you don't know the time it actually takes, you will replace both numerators with and x. (x/12 and x/18). You want to set these up so that they are adding. (x/12 + x/18=1). Since you're adding, you want to change it to the same denominator. The lowest is 36 so you multiply x/12 by 3/3 (so you don't unbalance the equation) and x/18 by 2/2. You'll end up with 3x/36 + 2x/36= 1 which will simplify to 5x/36=1. Multiply each side by 36 to leave the variable by itself. It becomes 5x=36 and when you divide it by 5 you get 7.2. So it's seven and .2 hours, which is equivalent to7 and 1/5 of an hour or 7 hours and 12 minutes.
Answer:
1 bag of 64
2 bags of 32
4 bags of 16
Or 8 bags of 8
Step-by-step explanation:
that's the answer I think for however your answer is there were no answers to pick from....
