We are given the ratio of 1/2 inch: 18 miles
Multiply both sides of the ratio by 2. I'm doing this so that the "1/2" turns into "1"
So we go from this ratio
1/2 inch: 18 miles
to this ratio
1 inch: 36 miles
which means that every inch on paper represents 36 miles in real life
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The question is now: if two towns are 2.5 inches apart on paper, then how far are they in real life? (note: 2.5 is the decimal form of 2 and a half)
To find out, multiply both sides by 2.5
1 inch: 36 miles
2.5*(1 inch): 2.5*(36 miles)
2.5 inches: 90 miles
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Answer: The two towns are 90 miles apart in real life
The answer is B ! as vertex is (6,3) and axis of symmetry lies on x=6 !
if you need explanation, comment !
Answer:
No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.
Step-by-step explanation:
"The Kolmogorov-Smirnov test (K-S) and Shapiro-Wilk (S-W) test are designed to test normality by comparing your data to a normal distribution with the same mean and standard deviation of your sample. If the test is NOT significant, then the data are normal, so any value above .05 indicates normality"
1360000 grams is the answer to that
Answer:
23 marbles
Step-by-step explanation:
Number of children = 10
Number of marbles = 180
Since Betsy gets the most and no 2 children gets the same number of marbles
The least number of marbles Betsy could get will be x ; with the other 9 children receiving 1 less each
That is :
Betsy = x
9th child = x - 1
8th child = x - 2,... 1st child = x - 9
Hence,
(x + x - 1 + x - 2 + x - 3 + x - 4 + x - 5 + x - 6 + x - 7 + x - 8 + x - 9) = 180
10x - 45 = 180
10x = 180 + 45
x = 225 / 10
x = 22.5
x = 23
Hence, the least Betsy could get is 23 marbles
