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34kurt
3 years ago
12

Consider two populations of coins, one of pennies and one of quarters. A random sample of 25 pennies was selected, and the mean

age of the sample was 32 years. A random sample of 35 quarters was taken, and the mean age of the sample was 19 years.
For the sampling distribution of the difference in sample means, have the conditions for normality been met?

(A) Yes, the conditions for normality have been met because the distributions of age for the two populations are approximately normal.
(B) Yes, the conditions for normality have been met because the sample sizes taken from both populations are large enough.
(C) No, the conditions for normality have not been met because neither sample size is large enough and no information is given about the distributions of the populations.
(D) No, the conditions for normality have not been met because the sample size for the pennies is not large enough and no information is given about the distributions of the populations.
(E) No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.
Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

D

Step-by-step explanation:

the sample size for the pennies is less than 30

Alexus [3.1K]3 years ago
5 0

Answer:

No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.

Step-by-step explanation:

"The Kolmogorov-Smirnov test (K-S) and Shapiro-Wilk (S-W) test are designed to test normality by comparing your data to a normal distribution with the same mean and standard deviation of your sample. If the test is NOT significant, then the data are normal, so any value above .05 indicates normality"

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Standard slope intercept form simplify all fractions <br> 2y-4x=-16
Shtirlitz [24]

Answer: y= 2x-8

Step-by-step explanation:

2y-4x=-16

2y=-16+4x

y=-8+2x

y= 2x-8

4 0
3 years ago
A metallurgist has one alloy containing 45% copper and another containing 69% copper. How many pounds of each alloy must be use
lakkis [162]

5.25 pounds of one alloy containing 45% copper and 36.75 pounds of 69% copper is used to make 42 pounds of 66% copper

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the amount of 45% copper and y represent the amount of 66% copper needed to make 42 pounds of a third alloy containing 66% copper. Hence:

x + y = 42   (1)

Also:

0.45x + 0.69y = 42(0.66)   (2)

This gives:

x = 5.25, y = 36.75

5.25 pounds of one alloy containing 45% copper and 36.75 pounds of 69% copper is used to make 42 pounds of 66% copper

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
How many pounds is 2.7 kilograms?
vampirchik [111]
The answer is 5.95248
6 0
3 years ago
Answer the question please.
Mariulka [41]

8/5x = 1

or

1.6x = 1

Work:

Add 7/3x and 1/3x to make 8/3x. Equation: 8/3x = 1 + 5/3x

Divide 8/3x by 5/3x, looks like 8 over 3 times 3 over 5. 3s cancel each other out, leaving 8/5x. Equation: 8/5x = 1

If needed to be simplified, 8/5 = 1.6.

6 0
3 years ago
33. A competition question requests students to form a three-digit number.
aniked [119]

Answer:

  532

Step-by-step explanation:

  532 = 2·2·7·19

__

There are 24 possible 3-digit numbers from the set {2, 3, 5, 7}. Of those, 6 have four factors: 372, 375, 532, 572, 732, 735.

The sums of factors of these numbers are ...

  38, 18, 30, 28, 68, 22

The number of interest is 532.

7 0
3 years ago
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