Answer: n=0 or n=2
Step-by-step explanation: Step 1: Subtract 2n from both sides.
n²−2n=2n−2n
n²−2n=0
Step 2: Factor left side of equation.
n(n−2)=0
Step 3: Set factors equal to 0.
n=0 or n−2=0
n=0 or n=2
Step-by-step explanation:
2,-1
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For the time period of the projectile at least 192 feet above the ground is between 2 second and 6 second
Since s=128t-16t2, we want to know the 2 times where 128t-16t2=192, as those two values will be the begin and end times of the interval in question. We can rewrite that equation in standard quadratic equation form:
16t2-128t+192=0 or, simplified, 8t2-64t+96=0
or t2-8t+12=0
since it is now in quadratic form, we can solve using the quadratic formula:
t = 2 and 6
So the time period from approximately 2 second and 6 second has the projectile above 192 feet.
Learn more about projectile here:
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Find the value of x. Bring x by itself.
-2x = -6
x = 3
Answer: 3 < x < 17
Step-by-step explanation: The lowest the side length could be is the difference between the other two. The highest it can be is the sum of the other two.