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34kurt
3 years ago
12

Consider two populations of coins, one of pennies and one of quarters. A random sample of 25 pennies was selected, and the mean

age of the sample was 32 years. A random sample of 35 quarters was taken, and the mean age of the sample was 19 years.
For the sampling distribution of the difference in sample means, have the conditions for normality been met?

(A) Yes, the conditions for normality have been met because the distributions of age for the two populations are approximately normal.
(B) Yes, the conditions for normality have been met because the sample sizes taken from both populations are large enough.
(C) No, the conditions for normality have not been met because neither sample size is large enough and no information is given about the distributions of the populations.
(D) No, the conditions for normality have not been met because the sample size for the pennies is not large enough and no information is given about the distributions of the populations.
(E) No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.
Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

D

Step-by-step explanation:

the sample size for the pennies is less than 30

Alexus [3.1K]3 years ago
5 0

Answer:

No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.

Step-by-step explanation:

"The Kolmogorov-Smirnov test (K-S) and Shapiro-Wilk (S-W) test are designed to test normality by comparing your data to a normal distribution with the same mean and standard deviation of your sample. If the test is NOT significant, then the data are normal, so any value above .05 indicates normality"

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Kristen has 64 coins in her bank. She has $9.25 in dimes and quarters. How many dimes and quarters does she have?
Stella [2.4K]
D= # of dimes
q= # of quarters

QUANTITY EQUATION:
d + q= 64

COST EQUATION:
0.10d + 0.25q= $9.25


STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2

(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40


STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q

Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40

0.15q= 2.85
divide both sides by 0.15

q= 19 quarters


STEP 3:
substitute q value in step 2 into either original equation to find d value

d + q= 64

d + 19= 64
subtract 19 from both sides

d= 45 dimes


CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25


ANSWER: There are 45 dimes and 19 quarters.

Hope this helps! :)
7 0
3 years ago
A town has a population of 19000 and grows at 4.5% every year. To the nearest tenth of a year, how long will it be until the pop
steposvetlana [31]

Answer:

If the population grows by 4% each year then

the population in any given year is 104% of

the previous year or 1.04 times as much

P(t) = P0(1.04)t

P(t) is population at time t years

P0 = initial population = 11,000

t = number of years = 15

P(15) = 11,000(1.04)15

P(15) = 19,810 people

Step-by-step explanation:

3 0
3 years ago
The distance between R and T on the coordinate grid is ___ units. (Input whole numbers only.)
gogolik [260]
15 units of distance. So 15
7 0
2 years ago
Which value is a solution of the equation 8y=56?
Korvikt [17]

Answer:

7

Step-by-step explanation:

If you divide 8y / 8  then you have to do the same thing to 56. When you do, y  = 7

3 0
3 years ago
While playing volleyball, Ralph drank 3/4 of a jug of water. If the jug held 64 fluid ounces of water, how much water did Ralph
arsen [322]

Answer:

48

Step-by-step explanation:

no explanation im just big brain

7 0
3 years ago
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