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Radda [10]
3 years ago
5

Studying for the act and I'm really bad at math, please help!

Mathematics
1 answer:
Bond [772]3 years ago
5 0
We are given the ratio of 1/2 inch: 18 miles

Multiply both sides of the ratio by 2. I'm doing this so that the "1/2" turns into "1"
So we go from this ratio
1/2 inch: 18 miles
to this ratio 
1 inch: 36 miles
which means that every inch on paper represents 36 miles in real life

----------------------------------------------------------------

The question is now: if two towns are 2.5 inches apart on paper, then how far are they in real life? (note: 2.5 is the decimal form of 2 and a half)

To find out, multiply both sides by 2.5
1 inch: 36 miles
2.5*(1 inch): 2.5*(36 miles)
2.5 inches: 90 miles

--------------------------------------------------------------------------

Answer: The two towns are 90 miles apart in real life
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Answer:

if the smaller one with ratio 4 cost 272 then eat will the larger one of ratio 5cost how much so u cross multiply 4 is for 272 so wat Abt 5 n u get 340 for the cost of the larger one

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14 times 4 times 18 times 6 times 5 Caleb draws $14 on each of 4 posters he draws 18 cats on each of six other posters if he dra
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Just add it all up with a calculator  
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3 years ago
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a used truck for $4,500 he made an agreement with the dealer to put $1,500 and make payments of 350 for the next 10 months that
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Ist amount paid = $1500
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I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
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3 0
3 years ago
Rob was tasked to graph this system of equations:
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Answer:

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5 0
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A rectangular stirp of asphalt paving is 5 meters longer than it is wide. its area is 300 square meters. find the length and wid
kow [346]
Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write
A=L\cdot W=300
Moreover, we know that the length is 5 meters longer than the width:
L=W+5
We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get
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L=W+5=15+5=20
<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
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3 years ago
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