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Dahasolnce [82]
3 years ago
5

Solve this equation. 2/3x-1/5x=x-1

Mathematics
2 answers:
Alona [7]3 years ago
5 0

Answer:

x = 15/8           -> Pls. when you post math questions out there, always tell what you need, otherwise, it becomes a guessing game. Are you trying to Factor/Simplify/Roots/Polynomials, etc? This doesn't pertain to this problem it's just a general statement.

Step-by-step explanation:

Solve for x:

(2 x)/3 - x/5 = x - 1

Put each term in (2 x)/3 - x/5 over the common denominator 15: (2 x)/3 - x/5 = (10 x)/15 - (3 x)/15:

(10 x)/15 - (3 x)/15 = x - 1

(10 x)/15 - (3 x)/15 = (10 x - 3 x)/15:

(10 x - 3 x)/15 = x - 1

10 x - 3 x = 7 x:

(7 x)/15 = x - 1

Multiply both sides by 15:

(15×7 x)/15 = 15 (x - 1)

(15×7 x)/15 = 15/15×7 x = 7 x:

7 x = 15 (x - 1)

Expand out terms of the right hand side:

7 x = 15 x - 15

Subtract 15 x from both sides:

7 x - 15 x = (15 x - 15 x) - 15

7 x - 15 x = -8 x:

-8 x = (15 x - 15 x) - 15

15 x - 15 x = 0:

-8 x = -15

Divide both sides of -8 x = -15 by -8:

(-8 x)/(-8) = (-15)/(-8)

(-8)/(-8) = 1:

x = (-15)/(-8)

Multiply numerator and denominator of (-15)/(-8) by -1:

Answer: x = 15/8

agasfer [191]3 years ago
4 0

Answer: 15+√645/30, 15-√645/30

Step-by-step explanation:

I hope this helps you sorry if it is wrong.

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Which expression uses the greatest common factor and the distributive property to rewrite the sum 7 + 75
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Answer:

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Step-by-step explanation:

Given

75 + 45 <em>-- Corrected</em>

Required

Use the GCF to write it as a distributive property

First, we find the GCF of 75 and 45

45 = 3 * 3 * 5

75 = 3 * 5 * 5

The common factor is:

GCF = 3 * 5

GCF = 15

So, 75 + 45 becomes

75 + 45 = 15 * 3 + 15 * 5

Factorize

75 + 45 = 15(3 + 5)

<em>Hence, the sum has been rewritten as </em>15(3 + 5)<em></em>

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A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

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