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Rainbow [258]
4 years ago
14

Two friends race against each other in 100-meter and 800-meter races. Of the 200 races they ran this year, the wins, losses, and

ties are shown below. 100 meter (Event D) 800 meter (Event E) A won the race (Event A) 30 50 B won the race (Event B) 60 25 A and B tied (Event T) 10 25 B did not win the race today. What length of race was it more likely to have been? 100 meter or 800 meter? How much more likely?
Mathematics
1 answer:
docker41 [41]4 years ago
4 0
<span>Let makes the table neater. event D= 100m, even E=800m
                                             (Event D) (Event E) 
A won the race (Event A)     30           50
B won the race (Event B)     60           25 
A and B tied (Event T)          10            25</span>

B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
Chance of B </span>did not win <span>100-m= 30+10/10=40%
</span>Chance of B did not win 800-m= 50+25/10=75%

The difference would be 75%-40%=35% more likely to lose 800-m race
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Answer:

25 and 21 hours respectively

Step-by-step explanation:

Let the number of hours worked by each welder be x and y respectively.

They worked a total of 46 hours. This means :

x + y = 46 hours.......(I)

Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:

34x + 39y = 1669........(ii)

We then solve both simultaneously. From I, x = 46 -y

We can substitute this into ii

34(46 -y) + 39y = 1669

1564 -34y + 39y = 1669

5y = 1669 - 1564

5y = 105

y = 105/5 = 21

x = 46 - y

x = 46 - 21 = 25 hours

The numbers of hours worked by the welders are 25 and 21 respectively

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The 3 in the above equation is like the G</span>
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