Company one cause the equation for it is y=0.04x. If you do y=0.04(500) u get 20$ as the total.
Answer:
Increase?
Step-by-step explanation:
Because think about it let's use 1/2 as an example.
1/2 equals .5 now lets add 2 to both the numerator and denominator
3/4 is the result and it also equals .75 which is larger than .5 so that's why the answer is increase.
and u can keep on going on with the method
4/5=.8
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
32.
V = L*w*h
Where:
V= Volume
L= Length = x+5
w= width = x-2
h= height = 6
Replacing with the values given:
V= (x+5) * (x-2) * 6
V =[ (x*x) + (x*-2) + (5*X) +5*-2) ] * 6
V= [ x^2 - 2x + 5x - 10 ] * 6
V= [ x^2 + 3x - 10] *6
V= (x^2*6) + (3x*6)+ ( - 10 * 6)
V= 6x^2 + 18x - 60