I need help answering this question please help

What are the answers I need help ?

olchik [2.2K]

Answer:

I can't see -_-

Step-by-step explanation:

I can't -_-

7 0

4 years ago

Given the parent functions f(x) = log3 (5x − 5) and g(x) = log3 (x − 1), what is f(x) − g(x)?. . a. f(x) − g(x) = log3 (4x − 4).

grandymaker [24]

$f ( x ) = log _{3} ( 5 x - 5 ), g ( x ) =log _{3} ( x - 1 ); \\ f ( x ) - g ( x ) = log _{3}( 5 x - 5 ) - log _{3}( x - 1 ) = \\ log _{3} \frac{5(x-1)}{x-1} = log _{3} 5$
Answer: C ) f ( x ) - g ( x ) = log3 5

8 0

3 years ago

Two Questions please help and explain

ozzi

Question #2
Erica will have to work for 14 hours in order to buy her sneakers.
How to solve:
You subtract $31 from $150 which equals to $119
You multiply 8.50 (which is the amount of money she gets paid every hour) by the answers they gave you.
8.50 multiplied by 14 is 199
Erica had to work 14 hours to make $199

Your answer is D) 14

4 0

4 years ago

Read 2 more answers

What is the shape of the graph of the function? h(t) = 0.32 - 0.5t

allsm [11]

Answer:

Answer (a) is correct

Step-by-step explanation:

This is not the same function that was given to you in the problem.

As you have typed it, this function is linear. The one in the homework problem is exponential.

We will ignore the linear function h(t) = 0.32 - 0.5t.

We will focus on h(t) = 0.32 - 0.5^t.

If t = 0, then 0.5^t = 0.5 ^0 = 1, and so h(0) = 0.32 - 1 = -0.68 => (0, -0.68)

Continuing with a few other t values chosen at random:

h(1) = -0.18

h(2) = 0.07

Notice that h is increasing as x increases!

h(4) = 0.2575

and so on.

answer A is the correct one.

h(1) = 0.32 - 0.5^1 = 0.32 - 0.5 = -0.18

4 0

3 years ago

The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

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To Find:

Curved surface area
Volume

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Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

Substituting the required values: 

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

Substituting the required values, 

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

8 0

2 years ago

Read 2 more answers