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astra-53 [7]
3 years ago
11

Plsss help meeeee 7^-8 divided by 7^-11

Mathematics
2 answers:
Andrej [43]3 years ago
4 0

Answer:

i think the answer is 7^3

Step-by-step explanation:

when dividing numbers with exponents, you just subtract the smaller exponent from the larger one

pls tell me if im wrong

jarptica [38.1K]3 years ago
4 0

Answer:

343

Step-by-step explanation:

7^-8/ 7^-11

7^ -8 - (-11)

7^3

Which equals 343

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The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.
nignag [31]

Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

x^2+6x=-9

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

x^2+6x+9=-9+9

The reason we do this is to create a perfect square binomial on the left:

(x+3)^2=0 (obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

(x+3)^2+0=y

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.

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3 years ago
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3 years ago
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

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3 years ago
What is 37,000 in scientific notation
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<span>3.7 x 10^<span>4 that is the answer</span></span>
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