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3 years ago

PLEASE HELP! Find the distance between each pair of points. Round your answers to the nearest tenth.

1 answer:

6 0

A.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\ = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }$

b.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\ \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\= 3 \frac{\sqrt{ 26 }}{ 2 }$

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3 years ago

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

ryzh [129]

Answer:

The third option is correct.

The domain of the function is given by

$Domain = 0 \leq t \leq 40$

The range of the function is given by

$Range = 0 \leq V(t) \leq 200$

Step-by-step explanation:

Sara bought a cell phone for $200 and its value has decreased at rate of $5 per month.

V(t) is the value of the phone and t is the number of months.

The domain of the function is the possible values of the number of months t.

The domain of the function is given by

$Domain = 0 \leq t \leq 40$

The range of the function is the values of V(t) that we get after substituting the possible values of the number of months t.

The range of the function is given by

$Range = 0 \leq V(t) \leq 200$

When the number of months is t = 0 then the value of the function is maximum V(t) = 200

When the number of months is t = 40 then the value of the function is minimum V(t) = 0

Therefore, the third option is correct.

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3 years ago

Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, trave

USPshnik [31]

Answer:

Julio travel 3 hours by biking and 4 hours by walking.

Step-by-step explanation:

Given:

Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, traveling 7 mph.

If the total trip to the park took 7 hours and it was 52 miles away.

Now, to find the time Julio travel at each speed.

The speed travelled by the bike = 8 mph.

The speed travelled by the walking = 7 mph.

Let the time Julio travel with bike be $x.$

And the time Julio travel by walking be $y.$

As, given Julio started biking to the park traveling, after some time the bike got a flat so Julio walked the rest of the way,

Thus, the total time taken:

$x+y=7$

$y=7-x\ \ \ .......(1)$

So, the distance travelled by bike:

Speed × time

$8\times x=8x$

And, the distance travelled by walking:

Speed × time

$7\times y=7y$

Now, the total distance travelled by Julio:

$8x+7y=52$

Substituting the value of $x$ from equation (1) we get:

$8x+7(7-x)=52$

$8x+49-7x=52\\\\x+49=52$

Subtracting both sides by 49 we get:

$x=3.$

The time Julio travelled with bike = 3 hours.

Now, to get the time Julio travelled by walking by substituting the value of $x$ :

$y=7-x\\\\y=7-3\\\\y=4\ hours.$

The time Julio travelled by walking = 4 hours.

Therefore, Julio travel 3 hours by biking and 4 hours by walking.

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3 years ago

Solve x2 - x - 30 = 0 by factoring.

likoan [24]

Answer:

x=6, x=-5

Step-by-step explanation:

Factoring this quadratic gets you (x-6)(x+5)=0, for this to be possible, either x-6 or x+5 has to be zero, so therefor x is 6, or x is -5

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