now, the angle of θ, can only have a "y" value that is positive on, well, y is positive at 1st and 2nd quadrants
and "x" is positive only in 1st and 4th quadrants
now, that angle θ, can only have those two fellows, "y" and "x" to be positive, only in the 1st quadrant, and also both to be negative on the 3rd quadrant.
and that those two fellows, can also be both negative in the 3rd quadrant
3/1 = 3, and -3/-1 = 3
so, the solutions can only be "3", when both "y" and "x" are the same sign, and that only occurs on the 1st and 3rd quadrants
1. Car Mart sell 11 cars per day.
You can use the table by looking at day 2 and day 3. You can see underneath it, it shows how many cars is left after that particular day. So from day 2, you have 43 cars left and day 3, you got 32 cars left. From 43 car to 32 car is losing 11 car. So each day the Car Mart sell 11 car.
2. First we know that after 3 days, Winston have 32 cars left and after 5 day, it has 12 cars left.
Here’s the chart that I made for Winston:
Each day, Winston’s sell 10 cars. (Lose 10 cars per day)
1) m=8d $40
2) d=15h 45 mi
3) less than one hour
Answer:
The second number ($1,541.02) is greater
Step-by-step explanation:
In the 100s place of the second number is a 5 and in the first a 4
Even though they have the same 1000s number 500 is larger that 400
Answer:
Step-by-step explanation:Wait im confused.
