All categories

3 years ago

Which sequence represents the correct levels of organization for multicellular organisms

1 answer:

6 0

Multicellular organisms have five levels of organization ranging from simplest to most complex. Level one is cells, level two is tissues, level three is organs, level four is organ systems, and level five is organisms.

You might be interested in

Select the true statements about SDS‑PAGE, a method of separating proteins. Assume that SDS‑PAGE is performed under reducing con

bazaltina [42]

Answer:

The correct statements are options C, E and F.

Explanation:

The SDS-PAGE refers to a broadly utilized technique for distinguishing proteins. The SDS or the sodium dodecyl sulfate refers to an ionic detergent. The SDS-protein complexes possess negative charge with identical charge to mass ratio such that when the proteins are run on the gel they are distinguished on the basis of their size.

As the SDS entices a negative charge to the proteins, the migration of the proteins takes place towards the positive electrode. The migration of protein takes place on the basis of the size. Thus, smaller proteins seem to migrate quickly via the gel in comparison to the bigger proteins. The binding of the protein takes place with about 1.4 times its mass of SDS resulting in the formation of a large overall negative charge.

4 0

3 years ago

Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

3 years ago

List the three statements that make up the Cell Theory.

torisob [31]

What three statements make up cell theory? The three statements are all living things are composed of cells, that cells are the basic units of structure and function in living things, and that new cells are produced from existing cells.

6 0

4 years ago

When Allison was completing her medical forms in the doctor's office, she was asked to indicate her race. What may be an appropr

poizon [28]

Answer: Strong links between race and health

Explanation:

Certain medical conditions like SICKLE CELL ANEMIA have been confirmed to be prevalent among people of AFRICAN descent.

Also, CYSTIC FIBROSIS have been known to be common among people of EUROPEAN race.

Therefore, Allison is required to include her race in the medical forms SO AS TO reveal any strong links her race has to do with her health

3 0

3 years ago

Is the understanding that knowledge in a particular area can be uncertain.

Artemon [7]

Hiya

I don't see how this is a question, can you please elaborate a bit? Thanks!

3 0

3 years ago

Read 2 more answers