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2 years ago

What does obsolete mean?

Computers and Technology

2 answers:

Alex2 years ago

8 0

No longer produced or used; out of date.

IrinaVladis [17]2 years ago

7 0

No longer produced or used; out of date."the disposal of old and obsolete machinery"synonyms:outdated, out of date, outmoded, old-fashioned, démodé, passé, out of fashion;

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Write a program, NumberStatistics.java, that reads an unspecified number of integers. The program ends with the input 0. The pro

Lerok [7]

Answer:

Following are the program, which can be below:

import java.util.*; //defining header file

public class NumberStatistics //defining class NumberStatistics

{

public static void main(String[] arc) //defining main method

{

int total_number=0,max_val=0,min_val=0,neg_val=0,pos_val=0,neg_count=0,pos_count=0,x; //defining variables

Scanner ox= new Scanner(System.in); //creating Scanner class Object

System.out.println("Enter positive and negative value with sign and when complete inter 0:"); //print message

x= ox.nextInt(); //input value from user

while(x!=0) //defining loop to check input value is 0

{

total_number++; // increment value

if(total_number == 1) //defining conditional statement to check minimum and maximum value

{

max_val = x; //assign value in max

min_val = x;//assign value in min

}

else //defining else block

{

if(max_val < x) //check maximum value

{

max_val = x; //assign maximum value

}

if(min_val > x) //check minimum value

{

min_val = x; //assign minimum value

}

if(x > 0) //input values

{

pos_count++; //count positive value

pos_val+=x; // add positive values

}

else

{

neg_count++;//count negative value

neg_val+=x; // add negative values

}

x = ox.nextInt(); //input values

}

// defining conditionl statement

if(total_number != 0) // defining if block to print all value

{

System.out.println("positive value average= "+(pos_val/(double)pos_count));

System.out.println("negative values Average= "+(neg_val/(double)neg_count));

System.out.println("all values average= "+(pos_val+neg_val)/(double)total_number);

System.out.println("maximum value = "+max_val+"\n"+" minimum value = "+min_val);

}

else

{

System.out.println("no positive values found");

System.out.println("no negative values found");

}

Output:

Enter positive and negative value with sign and when complete inter 0:

-22

-5

positive value average= 11.0

negative values Average= -13.5

all values average= 4.0

maximum value = 22

minimum value = -22

Explanation:

The Description of the above java program can be described as follows:

In the above code first we import the package for user input, then defines the variable "total_number,max_val,min_val,neg_val,pos_val,neg_count, pos_count,x" to store the value prints its value.
In the next step, a scanner class object is created for user input and defines a while loop, that checks input value isn't equal to 0, inside the loop a conditional statement defines that cont and calculates all positive, negative, and all values addition.
At the another conditional statement is defines, that prints all value average, and also prints maximum, minimum value.

6 0

3 years ago

____ a device receiving a process variable

Tanya [424]

Answer:

Transmitter

Maybe this is the answer or the question is wrong.

Explanation:

In the world of process control, a Transmitter is a device that converts the signal produced by a sensor into a standard instrumentation signal representing a process variable being measured and controlled.

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3 years ago

You have several marketing documents that are published through AD RMS. However, you have three new marketing employees that req

snow_lady [41]

Answer:

Document unauthorized

Explanation:

this way new employees will not try to open

5 0

3 years ago

You are most likely to use images for photos or digital paintings.

Lubov Fominskaja [6]

Answer: Digital Paintings

7 0

2 years ago

Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr

drek231 [11]

Answer:

Here is the C++ program:

#include <iostream> // to use input output functions

#include <cmath> // to use math functions like sqrt()

#include <iomanip> //to use setprecision method

using namespace std; //to access objects like cin cout

int main () { //start of main function

double speedA; //double type variable to store average speed of car A

double speedB; //double type variable to store average speed of car B

int hour; //int type variable to hold hour part of elapsed time

int minutes; //int type variable to hold minutes part of elapsed time

double shortDistance; // double type variable to store the result of shortest distance between car A and B

double distanceA; //stores the distance of carA

double distanceB; //stores the distance of carB

double mins,hours; //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl; //prompt user to enter the average speed of car A

cin >> speedA; //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ; //prompt user to enter the average speed of car B

cin >> speedB; //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl; //prompts user to enter elapsed time

cin>> hour >> minutes; //reads elapsed time in hours and minutes

mins = hour * 60; //computes the minutes using value of hour

hours = (minutes+mins)/60; //computes hours using minutes and mins

distanceA = speedA * (hours); // computes distance of car A

distanceB = speedB * (hours); //computes distance of car B

shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB)); //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;

This becomes

mins = 2 * 60

mins = 120

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

= 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

= sqrt(30625 + 18906.25)

= sqrt(49531.25)

= 222.556173

shortDistance = 222.56

Hence the output is:

The (shortest) distance between the cars is: 222.56

3 0

3 years ago