Someone pleasee help i only have less then 12 min to submit (::

I xyzdS trong đó S là phần mặt 2 2 z x y nằm giữa hai mặt phẳng z = 0 và z = 1

Anni [7]

Step-by-step explanation:

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$= . { {y1 {11.1 \times 3 { { {?}^{?} }^{?} }^{?} }^{?} }^{2} }^{2}$

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$22 {y)bvzv \cot( \beta log( \sec( log( \cot( \sec( \beta \alpha \pi \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( log(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) \times \frac{?}{?} }^{2}$

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4 0

2 years ago

Step by step workout of ; log x^3+log 5x=5 log 2-log 2/5

Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

$log \: {x}^{3} + log \: 5x = 5log \: 2 - log \: \frac{2}{5} \\ \\ \therefore \: log( {x}^{3} \times 5x) = log {2}^{5} - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log 32 - log \: \frac{2}{5} \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(32 \times \frac{5}{2} \bigg) \\ \\ \therefore \: log( 5{x}^{4}) = log \bigg(16 \times 5) \\ \\ \therefore \: 5{x}^{4}= 16 \times 5 \\ \\ \therefore \: {x}^{4}= {2}^{4} \\ \\ \huge \purple{ \boxed{\therefore \: {x} = 2}}$

4 0

2 years ago

the area of a rectangle is 28 ft squared, and the length of the rectangle is 5 ft less than 3 times the width. find the length a

forsale [732]

The length of the rectangle is 7 and the width is 4 and equation is this 3x4=12
12-5=7 and 7x4=28

3 0

3 years ago

Is qrs congruent to tuv if so name the postulate that applies

m_a_m_a [10]

Given triangles Q R S and T U V with segment QS congruant to T V, segment RS is congruent to segment U V and angle Q is congruent to angle T, thus the given congruency suggest A. S S or S S A which is not a complete reason for congruency.

Therefore, the two given triangles might not be congruent.

6 0

3 years ago

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Solve the following systems of equations using substitution: x = 6 y = 2x - 3

Stolb23 [73]

Answer:

y=9

Step-by-step explanation:

2(6)-3=9

6 0

2 years ago

Read 2 more answers