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2 years ago

Help!Ayuda!Tulong!....I need expiation pls

Mathematics

2 answers:

sineoko [7]2 years ago

7 0

Answer:

Step-by-step explanation:

B) a) 2, 5 , 8 , 11 ......

First term = 2

Second term = 5

Find the common difference.

Common difference = second term - first term

=5 - 2

= 3

Each term is obtained by adding 3 to the previous term.

11 + 3 = 14

14 + 3 = 17

17 +3 = 20

The next three terms are: 14 , 17 , 20

3) 1,4,16,64.....

This is a geometric sequence. Find the common ratio.

Common ratio = second term ÷ first term

= 4 ÷ 1

= 4

Each term is obtained by multiplying previous term by 4.

64 *4 = 256

256 *4 = 1024

1024 * 4 = 4096

The next three terms are: 256, 1024 , 4096.

4) 60, 48 , 36 , 24, .....

This is an arithmetic sequence.Find the common difference.

Common difference = 48 - 60

= -12

Each term is obtained by subtracting 12 ( adding -12) with the previous term.

24 - 12 = 12

12 - 12 = 0

0 - 12 = -12

The next three terms are: 12 , 0 , -12.

5) 1 , 4 , 9, 16,25 ,....

1, 2², 3², 4², 5².....

6² = 6*6 = 36

7² = 7*7 = 49

8² =8 * 8 = 64

The next three terms are: 36, 49 , 64.

kirza4 [7]2 years ago

5 0

It's a pattern- for example question 1 is adding 3 with each numer.
2 + 3 = 5
5+ 3= 8
8 + 3= 11
11+ 3 = 14
And so on

You gotta find the pattern and continue it :)

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Answer:

$12500

Step-by-step explanation:

use si formula

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3 years ago

Solve the system of equations. 10x+y=−20 y=2x2−4x−16 ( , ) and ( , )

Sladkaya [172]

I will go about solving this using the elimination method.

First, convert the equations.

10x + y = -20
4x + y = -12

Second, find the easiest variable to get rid of and get rid of it! (In this case, y) We will subtract to get rid of y.

6x = -8

Third, you want to solve the equation.

6x = -8 (divide by 6)
x = $-1 \frac{1}{3}$

Fourth, solve for y by inserting the answer for x into one of the equations.

10( $-1 \frac{1}{3}$ ) + y = -20
$-13 \frac{1}{3}$ + y = -20 (subtract $-13 \frac{1}{3}$ )
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3 years ago

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HELP AGAIN!!! Plzzzzz thank you!!!

never [62]

Absolute value of -1/3 is 1/3

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3 years ago

What is the solution to the expression -2-3-(-4)?

alexgriva [62]

Answer: -1

-2-3-(-4)
-5-(-4)
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3 years ago

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Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is:

$y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4$

$y = -5.333$

$(x,y) = (2, -5)$ does not belong to the function, the real point is $(x,y) = (2, -5.333)$ .

5 0

3 years ago

Help!Ayuda!Tulong!....​I need expiation pls

Help!Ayuda!Tulong!....I need expiation pls