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2 years ago

Which inequality is a true statement select each correct answer

Mathematics

1 answer:

stepan [7]2 years ago

4 0

Answer:

A. False

B. True

C. False

D. False

E. True

Hope This Helps!!!

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Brainlest if done all thank you

Shkiper50 [21]

#1: for x input:6,9,13. y=12,15,19 #2: for x input:0,3,7. y= -1,2,6, #3: for x input:0,6,12, y=0,18,36 #4: for x input:2,4,5. y=1,2,2.5 #5: 33

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3 years ago

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Which expression is equivalent to -3x(x-4) - 2x(x+3)

STatiana [176]

Answer:

-Xx95x-6)

Step-by-step explanation:

-3x(x-4) - 2x(x+3)

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3 years ago

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Who knows how to resolve this

Colt1911 [192]

You have to distribute the radical negative 18 in first. Simplifying from there, you’ll prob have to get into imaginary numbers since the square root of a negative is imaginary

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3 years ago

Test yourself 2

mafiozo [28]

Ok, so dy/dx=0 at the point (0,3) that is where x=0 and y=3.

$\int { 6x+6dx } \\ \\ =\frac { 6{ x }^{ 2 } }{ 2 } +6x+C\\ \\ =3{ x }^{ 2 }+6x+C$

$\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x+C$

Now, f'(x)=0 when x=0.

Therefore:

$0=C\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x$

Now:

$\int { 3{ x }^{ 2 } } +6xdx\\ \\ =\frac { 3{ x }^{ 3 } }{ 3 } +\frac { 6x^{ 2 } }{ 2 } +C$

$={ x }^{ 3 }+3{ x }^{ 2 }+C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+C$

But when x=0, y=3, therefore:

$3=C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+3$

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3 years ago

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Add a T-shirt stand on the boardwalk five of the last 10 shirt shirt sold we read what is the experimental probability that the

Hitman42 [59]

Answer:

1/2

Step-by-step explanation:

if 10 is 100%, 5 is 50% which is half

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