Question

Daud bought a plot of land with an area of 6 2/5 km. He divided the land equally into 8 small plots. What was the total area of 3 of the small plots of land?

Answer 1

Answer: $\dfrac{12}{5}\ km^2$

Step-by-step explanation:

Given

The area of land is $6\frac{2}{5}\ km^2$

Daud divide the land into 8 equal plots

So, the area of a single small plot is  

$\Rightarrow \dfrac{\dfrac{30+2}{5}}{8}\\\\\Rightarrow \dfrac{32}{5\times 8}\\\\\Rightarrow \dfrac{4}{5}\ km^2$

The area of three such plots

$\Rightarrow 3\times \dfrac{4}{5}\\\\\Rightarrow \dfrac{12}{5}\ km^2$