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hjlf
3 years ago
5

Three students are preparing information packets about an upcoming fundraiser event.

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0
Rate=amountdone/time

convert everybody to minutes
1 hour=60 minutes
45 mins=45 mins
1.5 hour=1.5 times 60=90mins
1hour and 10mins=60+10=70mins

laurenrate= 270packets/45mins=6ppm (packets per minute)
hannahrate=450packets/90mins=5ppm
jakobrate=280packets/70mins4ppm


whoever worked the fastest, has the highest ppm

lauren is winner


answer is A. lauren
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Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

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Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

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The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

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