Ask question

Ask question

All categories

3 years ago

5

Three students are preparing information packets about an upcoming fundraiser event.

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

Rate=amountdone/time

convert everybody to minutes
1 hour=60 minutes
45 mins=45 mins
1.5 hour=1.5 times 60=90mins
1hour and 10mins=60+10=70mins

laurenrate= 270packets/45mins=6ppm (packets per minute)
hannahrate=450packets/90mins=5ppm
jakobrate=280packets/70mins4ppm

whoever worked the fastest, has the highest ppm

lauren is winner

answer is A. lauren

You might be interested in

Help I understand but explain the steps and how you got it

ladessa [460]

Answer:

7-4 = 3

the change is 3 emails

Step-by-step explanation:

7 0

3 years ago

a fever is generally considered to be a body temperature greater than 100F . your friend has a temperature of 37C does your frie

svlad2 [7]

No he dose not because its 97 degrees f

4 0

3 years ago

Dana is shopping for clothes,she wants to buy a pair of shorts for $12 and plans to spend the rest on $7.50 tank tops.How many t

Juli2301 [7.4K]

Answer:

3 tank tops

Step-by-step explanation:

12 + 7.50 = $19.5

If you add 2 more of the 7.50 you will get

Answer: 34.5

so she will have enough for 3 tank tops if she doesn't want to buy 4 which would be $42.

6 0

3 years ago

there are 325 students each class is limited to at most 30 students. how many classes need to be offered?

podryga [215]

11 as the 25 need a class for it u can't leave 25 people 325÷30

3 0

3 years ago

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

5 0

2 years ago