The m variable is the slope of the line and controls its 'steepness'. A positive value has the slope going up to the right. A negative slope goes down to the right. The b variable is the y intercept - the point where the line crosses the y axis.

example 1

y = mx + b

m = slope b = y-intercept

y = 3x - 1

m = 3 and b = -1

example 2

y = b + mx 

b = y-intercept m = slope

y = 5 - 1/2x

m =- 1/2 and b = 5

(hope this helped!!)

can i have brainliest?

6 0

2 years ago

A random variable follows the continuous uniform distribution between 160 and 340. Calculate the following quantities for the di

Firlakuza [10]

Answer:

a) 0.3889

b) 0.5

c) 0.8333

d) The mean is 250 and the standard deviation is 51.96.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability of finding a value of X higher than x is:

$P(X > x) = 1 - \frac{x - a}{b-a}$

The probability of finding a value of X between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

The mean and the standard deviation are, respectively:

$M = \frac{a+b}{2}$

$S = \sqrt{\frac{b-a}^{2}{12}}$

A random variable follows the continuous uniform distribution between 160 and 340.

This means that $a = 160, b = 340$

$P(220 \leq X \leq 290) = \frac{290 - 220}{340 - 160} = 0.3889$

$P(160 \leq X \leq 250) = \frac{250 - 160}{340 - 160} = 0.5$

$P(X > 190) = 1 - \frac{190 - 160}{340 - 160} = 0.8333$

$M = \frac{160 + 340}{2} = 250$

$S = \sqrt{\frac{340 - 160}^{2}{12}} = 51.96$

The mean is 250 and the standard deviation is 51.96.

8 0

2 years ago