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Answer:
the interest earned= 93.401
and the future value of an annuity= 493.401
Step-by-step explanation:
Given Data:
Interest rate= 7%
time,t = 3 years
weekly payment, P= 400
At the end of 3 years, final investment A= ?
n= 52 as it is weekly
As per the interest formula
A= P(1+r/n)^nt
Putting value in above equation
=
= 493.401
Interest earned = A-P
= 493.401-400
= 93.401 !
The 3.1 °F/min rate of change of the temperature and 15 minutes change duration gives the change in temperature as 46.5 °F
<h3>How can the change in temperature be found from the rate of change?</h3>The rate at which the temperature changed = 3.1 °F/min
The duration of the change in temperature = 15 minutes
The relationship between the change in temperature, the rate of change in temperature and the time can be presented as follows;
Where;
∆T = The required change in temperature
∆t = The duration of the change = 15 minutes
Which gives;
∆T = 3.1°F/min × 15 minutes = 46.5 °F
- The change in temperature, ∆T = 46.5 °F
Learn more about the rate of change of a variable here:
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Answer:
The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).
98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.
Step-by-step explanation:
The first step is finding the confidence interval
The sample size is 103.
The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So
Then, we need to subtract one by the confidence level and divide by 2. So:
Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have .
Now, we need to find the standard deviation of the sample. That is:
Now, we multiply T and s
For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.
For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.
The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).
98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.