Well im not to sure about this one loook it up
Answer:
According to AD=BC So AC=BD
Step-by-step explanation:
AD = BC and angle ADC = angle BCD
we have to prove AC = BD
let's see ∆ADC and ∆BCD
AD = BC [ given ]
angle ADC = angle BCD [ given ]
CD = CD
from S - A - S
∆ADC congruence ∆BCD
Answer:
A
Step-by-step explanation:
Given 2 secants from a point outside the circle.
Then the product of the external part and the entire secant of one secant is equal to the product of the external part and the entire secant of the other secant, that is
(x + 1)(x + 1 + 11) = (x + 4)(x + 4 + 1)
(x + 1)(x + 12) = (x + 4)(x + 5) ← expand both sides
x² + 13x + 12 = x² + 9x + 20 ← subtract x² + 9x from both sides
4x + 12 = 20 ( subtract 12 from both sides )
4x = 8 ( divide both sides by 4 )
x = 2 → A
C. 5/2, 3 this is the answer