Answer:
A = 3
B = 1
C = 2
D = 10
E = 2
F = Not listed
G = 1
Step-by-step explanation:
![\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B270x%5E5y%5E7%7D%20%3D%5Csqrt%5B3%5D%7B27%2A10x%5E5y%5E7%7D%3D3xy%5E2%5Csqrt%5B3%5D%7B10x%5E2y%7D)
Answer: -630
Step-by-step explanation:
Given the nth term of a sequence;
a(n)=a(n−1)⋅(−9) and the first term of the sequence a(1) as 35, the third term of the sequence can be gotten by using the formula at when n = 3
If n = 3 and a(1) = 35;
a(3) = 35(3-1)•(-9)
a(3) = 35×2×-9
a(3) = 70×-9
a(3) = -630
There the 3rd term of the series will give us -630 according to the nth term of the formula given.
Answer:
X
=
27
Step-by-step explanation:
7x=2+4
7x=6
X=6/7 ans
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