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Virty [35]
3 years ago
14

Ellie is preheating her oven before using it to bake. The initial temperature of the oven is 65° and the temperature will increa

se at a rate of 10° per minute after being turned on. What is the temperature of the oven 6 minutes after being turned on? What is the temperature of the oven tt minutes after being turned on?
Mathematics
1 answer:
sineoko [7]3 years ago
7 0

Answer:

Temp after 6 minutes: 125 degrees              Temp after tt minutes: 65 + 10t

Step-by-step explanation:

65 x 10(6) = 125

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vlabodo [156]
Four plus the absolute value of twenty-seven minus ten
3 0
3 years ago
The bearing of Q from P is 150
Lynna [10]

Answer:

(i) see first attached diagram

(ii) QR = 22.67 km (2 dp)

(iii) 243°

Step-by-step explanation:

A bearing is the angle in degrees measured clockwise from north.

<u />

<u>Part (i)</u>

see first attached diagram

<u>Part (ii)</u>

The angles marked in blue on the second attached diagram are Consecutive Interior Angles.  In this case they add to 180° as the North lines are parallel.

The sum of angles around a point is 360°

⇒ m∠QPR (shown in red on the second attached diagram) = 360 - 150 - (180 - 15) = 45°        

To calculate the distance between Q and R (marked in red on the attached diagram), use the cosine rule.

⇒ QR² = PR² + QP² - 2(PR)(QP)cos(QPR)

⇒ QR² = 32² + 24² - 2(32)(24)cos(45)

⇒ QR² = 513.8839841...

⇒ QR = √513.8839841...

⇒ QR = 22.67 km (2 dp)

<u>Part (iii)</u>

We need to find the angle marked in green on the third attached diagram.

To do this, we need to find the angle marked in pink and the angle marked in orange, then subtract them from 360°

Pink angle = 180 - 150 = 30° (using the same consecutive angle theorem as before)

Orange angle (o) using the sine rule:

⇒ sin(o)/32 = sin(45)/QR

⇒ sin(o) = 32sin(45)/22.67

⇒ sin(o) = 0.9981652337...

⇒ o = 86.52868176...°

Therefore, the green angle = 360 - 30 - 86.52868176... = 243° (nearest degree)

8 0
2 years ago
Write the equation of the line for a line that passes through (-2,-4) and (-1, -1).
Bas_tet [7]

Answer:

y = 3x+2

Step-by-step explanation:

First find the slope using the slope formula

m= (y2-y1)/(x2-x1)

   = ( -1 - -4)/(-1 - -2)

   = (-1 +4)/ (-1 +2)

   = 3/1

  = 3

The slope intercept formula is

y = mx+b where m is the slope and b is the y intercept

y = 3x+b

Using the point (-1,-1) and substituting into the equation

-1 = 3(-1)+b

-1 = -3+b

-1+3 = b

2 = b

y = 3x+2

3 0
2 years ago
Which of the following functions is graphed below?
Varvara68 [4.7K]

Answer:

what  are you trying to ask?

Step-by-step explanation:

8 0
3 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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