Answer: D. There are at least two oatmeal cookies next to each other.
Step-by-step explanation:
Alright so basically we can use process of elimination to determine what is true or false so
A. States the farthest to the left is chocolate but we can't prove that because all we know is the cookie farthest to the right is chocolate so this is<u> false</u>
B. Same reason as A we cannot prove what cookie is farthest to the left because we are not given a pattern so <u>B is false</u>
C. Since there are definitely twice as many girls as boys in the class and that also means there are twice as many oatmeal cookies then we cannot prove that 2 chocolate cookies have to be next to each other<u> so also false</u>
<u></u>
D. This has to be true because if there are twice as many girls as boys and more oatmeal than chocolate then is whatever cookie line combinataion we will have at least 2 oatmeal cookies next to each other So this is true
E. This is most definitely not true because the question tells us that twice as many girls gave him oatmeal so if anything there are more oatmeal cookies
C; 120 because 24x=360 so x=15. Then ABC is 8x, so 8*15=120.
Answer:
Do you have options? The answer would be
g(x)=(x/3)^2
x = 1 btw
Because x = 1, if you have options then it'll most likely be g(x)=(1/3]^2
Step-by-step explanation:
Hope this helps
Write a recursive and explicit formula for each option.
Save a nickel on the first day of the month and then double the amount each day for a month
=> a1 =0.05
=> a2 = a1* 2 = 0.05*2
=> a3 = a2*2 = a1* 2*2
..............................................
=>recursive an = 
=> explicit an = 0.05*
Start their savings by saving $10 on the first day and then $10 each day of the month
=> a1 = 10
=> a2 = a1 + 10 = 20
=> a3 = a2 +10 = 20 +10 =30
........................................................
=> recursive an = 
=> explicit an = 10 + 10( n-1)
Hope it will find you well.
