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mixer [17]
3 years ago
9

Find the slope of the line. 5x – 2y = 7

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0

Answer:

Final answer is slope m=\frac{5}{2}

Step-by-step explanation:

Given equation is 5x-2y=7

Now question says to find the slope.

Since given equation 5x-2y=7 is a linear equation so we need to compare 5x-2y=7 with slope intercept formula y=mx+b to get the value of slope m.

Since 5x-2y=7 is not in that form so first let's rewrite it in y=mx+b form

5x-2y=7

-2y=-5x+7

y=\frac{-5x+7}{-2}

y=\frac{5}{2}x-\frac{7}{2}

Now comparing with y=mx+b, we get m=\frac{5}{2}

Hence final answer is slope m=\frac{5}{2}

gtnhenbr [62]3 years ago
7 0

Answer:

Slope = 5/2

Step-by-step explanation:

It is given an equation of line  5x – 2y = 7

To find the slope of equation we have to rewrite this equation in y = mx + c form

<u>To convert the given equation to y = mx + c</u>

The given equation is

 5x – 2y = 7

⇒ 5x + 7 = 2y

⇒ 2y = 5x + 7

⇒ y = (5x + 7)/2

y = 5x/2 + 7/2

The above equation is of the form y = mx + c

Here slope = m = 5/2

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Answer:

(a) The value of P (X < 21 | <em>μ </em> = 23 and <em>σ</em> = 3) is 0.2514.

(b) The value of P (X ≥ 66 | <em>μ </em> = 50 and <em>σ</em> = 9) is 0.0427.

(c) The value of P (X > 47 | <em>μ </em> = 50 and <em>σ</em> = 5) is 0.7258.

(d) The value of P (17 < X < 24 | <em>μ </em> = 21 and <em>σ</em> = 3) is 0.7495.

(e) The value of P (X ≥ 95 | <em>μ </em> = 80 and <em>σ</em> = 1.82) is 0.

Step-by-step explanation:

The random variable <em>X</em> is Normally distributed.

(a)

The mean and standard deviation are:

\mu=23\\\sigma=3

Compute the value of P (X < 21) as follows:

P(X

                  =P(Z

Thus, the value of P (X < 21 | <em>μ </em> = 23 and <em>σ</em> = 3) is 0.2514.

(b)

The mean and standard deviation are:

\mu=50\\\sigma=9

Compute the value of P (X ≥ 66) as follows:

Use continuity correction.

P (X ≥ 66) = P (X > 66 - 0.5)

                = P (X > 65.5)

                =P(\frac{X-\mu}{\sigma}>\frac{65.5-50}{9})

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Thus, the value of P (X ≥ 66 | <em>μ </em> = 50 and <em>σ</em> = 9) is 0.0427.

(c)

The mean and standard deviation are:

\mu=50\\\sigma=5

Compute the value of P (X > 47) as follows:

P(X>47)=P(\frac{X-\mu}{\sigma}>\frac{47-50}{5})

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Thus, the value of P (X > 47 | <em>μ </em> = 50 and <em>σ</em> = 5) is 0.7258.

(d)

The mean and standard deviation are:

\mu=21\\\sigma=3

Compute the value of P (17 < X < 24) as follows:

P(17

                          =P(-1.33

Thus, the value of P (17 < X < 24 | <em>μ </em> = 21 and <em>σ</em> = 3) is 0.7495.

(e)

The mean and standard deviation are:

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Compute the value of P (X ≥ 95) as follows:

Use continuity correction:

P (X ≥ 95) = P (X > 95 - 0.5)

                = P (X > 94.5)

                =P(\frac{X-\mu}{\sigma}>\frac{94.5-80}{1.82})

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Thus, the value of P (X ≥ 95 | <em>μ </em> = 80 and <em>σ</em> = 1.82) is 0.

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